大家看看这个哪里错误了
AsminuserDAO中的一个方法
public List findByStr(String queryString, Map paramMap) {
// TODO 自动生成方法存根
log.debug( "finding Adminuser by String sql: ");
try {

return getHibernateTemplate().find(queryString, paramMap);//是不是这句有问题
} catch (RuntimeException re) {
log.error( "find by property name failed ", re);
throw re;
}


}


被另一个程序调用
public class ServiceImp implements IService {
private AdminuserDAO adminuserDAO;
public AdminuserDAO getAdminuserDAO(){
return adminuserDAO;
}
public void setAdminuserDAO(AdminuserDAO adminuserDAO){
this.adminuserDAO=adminuserDAO;
}
//private static String hql = "from vo.Adminuser u where u.UserName=? ";

public boolean isAdmin(String username, String password) {


String queryString= "from Adminuser as model where model.userName=? and password=? ";
Map paramMap = new HashMap();

paramMap.put( "userName ", username);
paramMap.put( "password ", password);
List AdminList=adminuserDAO.findByStr(queryString, paramMap);
if (AdminList.size()> 0) {

return true;

}

return false;

}

}

错误信息是
javax.servlet.ServletException: Expected positional parameter count: 2, actual parameters: [{userName=maxin, password=maxin}] [from Adminuser as model where model.userName=? and password=?]; nested exception is org.hibernate.QueryException: Expected positional parameter count: 2, actual parameters: [{userName=maxin, password=maxin}] [from Adminuser as model where model.userName=? and password=?]
大家多多指教谢谢

[解决办法]
Map paramMap = new HashMap();
别用这个

用Object[] ob = new Object[]{username, password};

最好的还是封装到一个FROMBEAN里或者POJO类里