自己看视频学struts+hibernate仿照着写个最简单的例子都报错啊救我啊！
主要是这里啊

/*
* Generated by MyEclipse Struts
* Template path: templates/java/JavaClass.vtl
*/
package com.jhkj.struts.action;

import java.util.Iterator;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.apache.struts.action.Action;
import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionForward;
import org.apache.struts.action.ActionMapping;
import org.hibernate.Query;
import org.hibernate.Session;
import org.hibernate.Transaction;

import com.jhkj.HibernateSessionFactory;
import com.jhkj.Userlist;

/**
* MyEclipse Struts
* Creation date: 06-22-2007
*
* XDoclet definition:
* @struts.action validate= "true "
*/
public class LoginAction extends Action {
/*
* Generated Methods
*/

/**
* Method execute
* @param mapping
* @param form
* @param request
* @param response
* @return ActionForward
*/
public ActionForward execute(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response) {
// TODO Auto-generated method stub
//获取提交的用户名称和密码
String userName=request.getParameter( "userName ");
String userPwd=request.getParameter( "userPwd ");
System.out.println( "用户名 "+userName+ "密码 "+userPwd);
String mUserPwd=null;
Userlist ul=null;
//创建连接
Session session=HibernateSessionFactory.getSession();
//创建事务
Transaction tx=session.beginTransaction();
//创建对话
Query query=session.createQuery( "select u from Userlist as u where username= ' " +
userName + " ' ");
try{
//Iterator it = query.iterate();
//ul = (Userlist) it.next();
//mUserPwd=ul.getUserpwd();
Userlist uk=(Userlist)query.uniqueResult();
mUserPwd=uk.getUserpwd();
}catch (Exception e) {
System.out.println( "异常信息： "+e.getMessage());
}
if(userPwd.equals(mUserPwd))
request.setAttribute( "loginOk ", "Hello " + ul.getUsername());
else
request.setAttribute( "loginOk ", "Login Error! ");
//事务提交
tx.commit();
//关闭连接
HibernateSessionFactory.closeSession();
return mapping.findForward( "success ");
}
}


//Iterator it = query.iterate();
//ul = (Userlist) it.next();
//mUserPwd=ul.getUserpwd();

用上面这个获得密码报
could not execute query using iterate
这个错误
查了好多资料用这个拉
Userlist uk=(Userlist)query.uniqueResult();

mUserPwd=uk.getUserpwd();
可是又报这个错误
could not execute query

我真的解决不了拉 啊！
帮我下！


[解决办法]
配制文件和HibernateSessionFactory是怎么写的？该用的JAR包都放到LIB下了吗
[解决办法]
//创建对话
Query query=session.createQuery( "select u from Userlist as u where username= ' " +
userName + " ' ");

select u from Userlist as u
这句没问题吗？感觉怪怪D.
[解决办法]
应该这样子吧select u as u from Userlist
[解决办法]
Iterator it = query.list().iterate();
[解决办法]
是下面的包没错
[解决办法]
QQ111712
[解决办法]
AddAction.java:51

这个地方空指针了