紧急求助：postgre的serial类型的映射问题。
我百思不得其解，为什么每次总出线这个错误。我已经照n个这样的例子进行修改了。serial类型是映射成Integer类型的。可报的这个错误，实在搞不明白。哪位高人帮忙看看。
简单的一个查询语句：
Object users = getHibernateTemplate().get(User.class, user);


User.hbm.xml：
<?xml version= "1.0 "?>
<!DOCTYPE hibernate-mapping PUBLIC
"-//Hibernate/Hibernate Mapping DTD 3.0//EN "
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd " >

<hibernate-mapping package= "freeunite.hibernate ">
<class name= "User " table= "USER ">
<id
column= "ID "
name= "id "
type= "java.lang.Integer "
>
<generator class= "native " />
</id>
<property
column= "PASSWORD "
length= "30 "
name= "password "
not-null= "false "
type= "java.lang.String "
/>
<property
column= "REMARKS "
length= "50 "
name= "remarks "
not-null= "false "
type= "string "
/>
<property
column= "USER_ID "
length= "15 "
name= "userId "
not-null= "true "
type= "java.lang.String "
/>
<property
column= "ROLE "
length= "10 "
name= "role "
not-null= "false "
type= "java.lang.String "
/>
<property
column= "USER_NAME "
length= "20 "
name= "userName "
not-null= "false "
type= "java.lang.String "
/>
</class>
</hibernate-mapping>

User.java:
public class User implements Serializable {

private Integer id;

private String userId;

private String userName;

private String password;

private String role;

private String remarks;

public Integer getId() {
return id;
}

public void setId(Integer id) {
this.id = id;
}

public String getPassword() {
return password;
}

public void setPassword(String password) {
this.password = password;
}

public String getRemarks() {
return remarks;
}

public void setRemarks(String remarks) {
this.remarks = remarks;
}

public String getRole() {
return role;
}

public void setRole(String role) {
this.role = role;
}

public String getUserId() {
return userId;
}

public void setUserId(String userId) {
this.userId = userId;
}

public String getUserName() {
return userName;
}

public void setUserName(String userName) {
this.userName = userName;

}

}

错误信息：
org.hibernate.TypeMismatchException: Provided id of the wrong type. Expected: class java.lang.Integer, got class freeunite.hibernate.User
at org.hibernate.event.def.DefaultLoadEventListener.onLoad(DefaultLoadEventListener.java:86)
at org.hibernate.impl.SessionImpl.fireLoad(SessionImpl.java:878)
at org.hibernate.impl.SessionImpl.get(SessionImpl.java:815)
at org.hibernate.impl.SessionImpl.get(SessionImpl.java:808)
at org.springframework.orm.hibernate3.HibernateTemplate$1.doInHibernate(HibernateTemplate.java:467)
at org.springframework.orm.hibernate3.HibernateTemplate.execute(HibernateTemplate.java:369)
at org.springframework.orm.hibernate3.HibernateTemplate.get(HibernateTemplate.java:461)
at org.springframework.orm.hibernate3.HibernateTemplate.get(HibernateTemplate.java:455)
at freeunite.dao.UserDAOImpl.findUserById(UserDAOImpl.java:21)
at freeunite.service.LoginServiceImpl.findUserById(LoginServiceImpl.java:19)
at freeunite.service.LoginServiceImpl$$FastClassByCGLIB$$4f9b58de.invoke( <generated> )
at net.sf.cglib.proxy.MethodProxy.invoke(MethodProxy.java:149)
at org.springframework.aop.framework.Cglib2AopProxy$CglibMethodInvocation.invokeJoinpoint(Cglib2AopProxy.java:693)
at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:139)
at org.springframework.transaction.interceptor.TransactionInterceptor.invoke(TransactionInterceptor.java:107)
at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:161)
at org.springframework.aop.framework.Cglib2AopProxy$DynamicAdvisedInterceptor.intercept(Cglib2AopProxy.java:628)
at freeunite.service.LoginServiceImpl$$EnhancerByCGLIB$$6ae9edaa.findUserById( <generated> )
at freeunite.action.LoginAction.login(LoginAction.java:54)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)



[解决办法]
ding