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请教怎么从OpenFileDialog中读取所有文

发布时间: 2011-12-24 23:03:24 作者: rapoo

请问如何从OpenFileDialog中读取所有文件名到Listbox
Private Sub Button3_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button3.Click
On Error Resume Next
With OpenFileDialog1
.Multiselect = True
.FileName = " "
.Filter = "Excel文件(*.xls)|*.xls "
.FilterIndex = 1
End With
OpenFileDialog1.ShowDialog()
ListBox1.Items.Add(OpenFileDialog1.FileName)
End Sub

请问如何从OpenFileDialog中读取所有文件名到Listbox?


[解决办法]
那你用选取文件夹的方式好了。。。。

FolderBrowserDialog:

If Me.FolderBrowserDialog1.ShowDialog() = DialogResult.OK Then
Me.ListBox1.DataSource = IO.Directory.GetFiles(Me.FolderBrowserDialog1.SelectedPath)
End If
[解决办法]
With OpenFileDialog1
.Multiselect = True
.FileName = " "
.Filter = "Excel文件(*.xls)|*.xls "
.FilterIndex = 1
End With
OpenFileDialog1.ShowDialog()

ListBox1.Items.AddRange(OpenFileDialog1.FileNames)

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