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serlet访问不了jsp

发布时间: 2011-12-31 23:50:30 作者: rapoo

serlet访问不了jsp,高手指点
这是完正的程序代码帮忙看看
package my_home;

import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
import java.util.*;

public class news_add_get extends HttpServlet {

public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException
{
String nesws_art=request.getParameter( "art ");
System.out.println(nesws_art);

}
//Clean up resources
public void destroy() {
}
}


服务器报错:StandardHost[localhost]: MAPPING configuration error for request URI
StandardHost[localhost]: Removing web application at context path /web_home

*****************************
这是JSP里的完正的代码

<%@ page contentType= "text/html; charset=GBK " %>
<html>
<head>
<title>
update_index_news
</title>
<style type= "text/css ">
<!--
.style1 {
font-size: 18px;
font-family: "黑体 ";
}
.style4 {font-family: "黑体 "; font-size: 16px; }
-->
</style>
</head>
<table width= "768 " border= "2 " align= "center ">
<form action= "/my_home/news_add_get " >
<p>   </p>
<p>   </p>
<p>   </p>
<tr align= "center " valign= "middle ">
<td width= "200 " height= "30 "> <span class= "style4 "> 新闻标题名 </span> </td>
<td valign= "middle ">       
<input name= "art " type= "text " size= "50 ">
   最多14个字 </td>
</tr>
<tr align= "center " valign= "middle ">
<td height= "30 "> <span class= "style4 "> 发表  作者 </span> </td>
<td valign= "middle ">        <input name= "author_news " type= "text " size= "50 ">
   最多10个字 </td>
</tr>
<tr align= "center " valign= "middle ">


<td height= "30 "> <p class= "style1 "> 新 </p>
<p class= "style1 "> 闻 </p>
<p class= "style1 "> 内 </p>
<p class= "style1 "> 容 </p> </td>
<td valign= "middle "> <textarea name= "date_news " cols= "55 " rows= "10 " > </textarea> </td>
</tr>
<tr align= "center " valign= "middle ">
<td height= "30 ">   </td>
<td valign= "middle ">
<input type= "submit " name= "Submit " value= "提交 ">
             
<input type= "reset " name= "Submit2 " value= "取消 "> </td>
</tr>
</form>
</table>
</body>
</html>
****************************
这是WEB.xml 文件

<?xml version= "1.0 " encoding= "UTF-8 "?>
<!DOCTYPE web-app PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN " "http://java.sun.com/dtd/web-app_2_3.dtd ">
<web-app>
<display-name> web_home </display-name>

<servlet>
<servlet-name> news_add_get </servlet-name>
<servlet-class> my_home.my_home.news_add_get </servlet-class>
</servlet>

<servlet-mapping>
<servlet-name> news_add_get </servlet-name>
<url-pattern> /news_add_get </url-pattern>
</servlet-mapping>
</web-app>


请各位专家帮我会诊1111111111111



[解决办法]
应该是路径的问题,试试这个技巧,右建运行news_add_get就会得出servlet的路径

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