|M| 防止按钮二次提交时,验证控件对这个按钮就无效了 怎么办 谢谢
<script type= "text/javascript ">
var option= "Once ";
function Twice()
{
if(option== "Once ")
{
//document.all( "btnOk ").Enable = false;
return false;
}
option = "Once ";
}
</script>
<asp:Button ID= "btnOk " Text= "保存 " runat= "server " OnClick= "btnOk_Click " OnClientClick= " return Twice() "> </asp:Button>
点击保存的时候就直接跑过验证了
问题应该在OnClientClick= " return Twice() " 这里
[解决办法]
不要写在button的click中
写在form的 onsubmit 中
<form name= "test " runat= "server " onsubmit= "return Twice(); ">
[解决办法]
有个替代的方式，就是用VS自带的验证控件。
[解决办法]
用Custom验证控件，这样只需要将你上面的JS函数名赋给验证控件就可以了 ！
[解决办法]
不能使用asp.net服务器 button 改成input button runat=server
<%@ Page Language= "C# " AutoEventWireup= "true " CodeFile= "testButtonEnable.aspx.cs " Inherits= "testButtonEnable " %>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN " "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd ">
<html xmlns= "http://www.w3.org/1999/xhtml " >
<head runat= "server ">
<title> 无标题页 </title>
<script type= "text/javascript ">
var option= "Once ";
function Twice()
{
alert(option);
if(option== "Once ")
{
document.all( "Button1 ").disabled = true;
option = "Twice ";
return true;
}
//option = "Once ";
return false;
}
</script>
</head>
<body>
<form id= "form1 " runat= "server " onsubmit= "return Twice(); ">
<div>
<asp:TextBox ID= "TextBox1 " runat= "server "> </asp:TextBox>
<asp:RequiredFieldValidator ID= "RequiredFieldValidator1 " runat= "server " ControlToValidate= "TextBox1 "
ErrorMessage= "RequiredFieldValidator "> </asp:RequiredFieldValidator> <br />
<input id= "Button1 " runat= "server " onserverclick= "Button1_ServerClick " type= "button "
value= "button " /> </div>
</form>
</body>
</html>
[解决办法]
jedliu(21世纪什么最贵? 人才!) ( ) 信誉：982007-05-16 16:37:22得分:0
?用Custom验证控件，这样只需要将你上面的JS函数名赋给验证控件就可以了 ！
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这东西在ff上支持不太好
[解决办法]
在你的脚本最后加上return WebForm_DoPostBackWithOptions(new WebForm_PostBackOptions(event.srcElement.id, " ", true, " ", " ", false, false));
[解决办法]
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