求利用C＃创建一个XML并保存到XML文件中的代码
要求如下：创建一个叫abc.xml的文档，然后根节点叫root，在根结点下创建一个 <a> 结点， <a> 节点有个b属性，属性值是123，然后把这个xml文档保存到文件中。

[解决办法]

XmlTextWriter myWriterxsl = new XmlTextWriter(@ "E:\testxsl.xml ", Encoding.UTF8);
myWriterxsl.Formatting = Formatting.Indented;
myWriterxsl.WriteStartDocument();

myWriterxsl.WriteStartElement( " ", "root ", " ");
myWriterxsl.WriteStartElement( " ", "a ", " ");
myWriterxsl.WriteAttributeString( "b ", "123 ");
myWriterxsl.WriteEndElement();
myWriterxsl.WriteEndDocument();
myWriterxsl.Flush();
myWriterxsl.Close();
[解决办法]
http://www.pconline.com.cn/pcedu/empolder/net/0406/388296.html
[解决办法]
需要用到XmlNode和XmlAttribute两个类