帮忙！临时表问题
下面的sql，能否不用临时表？


select XZJD_MC, B.jfxzc_mc,B.JFXZC_MJ,B.QX_DM,B.zq_dm,B.jfxzc_dm,
(select sum(tb_mj) from ST_DLTB where DL_DM= '111 ' and SZXZC_DM=JFXZC_MC group by JFXZC_MC)as e111,
(select sum(tb_mj) from ST_DLTB where DL_DM= '325 ' and SZXZC_DM=JFXZC_MC group by JFXZC_MC)as cw325
into #ccc
from st_xzorjd as A
inner join st_jforxzc B on SUBSTRING(A.XZJD_DM,7,3)=B.zq_dm

select xzjd_mc,sum(jfxzc_mj)as jfxzc_mj,sum(e111) as e111,sum(cw325) as cw325
from #ccc
group by xzjd_mc

drop table #ccc


非常感谢

[解决办法]
可以

select xzjd_mc,sum(jfxzc_mj)as jfxzc_mj,sum(e111) as e111,sum(cw325) as cw325
from
(
select XZJD_MC, B.jfxzc_mc,B.JFXZC_MJ,B.QX_DM,B.zq_dm,B.jfxzc_dm,
(select sum(tb_mj) from ST_DLTB where DL_DM= '111 ' and SZXZC_DM=JFXZC_MC group by JFXZC_MC)as e111,
(select sum(tb_mj) from ST_DLTB where DL_DM= '325 ' and SZXZC_DM=JFXZC_MC group by JFXZC_MC)as cw325
from st_xzorjd as A
inner join st_jforxzc B on SUBSTRING(A.XZJD_DM,7,3)=B.zq_dm
) B
group by xzjd_mc
[解决办法]
select xzjd_mc,sum(jfxzc_mj)as jfxzc_mj,sum(e111) as e111,sum(cw325) as cw325 from
(
select XZJD_MC, B.jfxzc_mc,B.JFXZC_MJ,B.QX_DM,B.zq_dm,B.jfxzc_dm,
(select sum(tb_mj) from ST_DLTB where DL_DM= '111 ' and SZXZC_DM=JFXZC_MC group by JFXZC_MC)as e111,
(select sum(tb_mj) from ST_DLTB where DL_DM= '325 ' and SZXZC_DM=JFXZC_MC group by JFXZC_MC)as cw325
from st_xzorjd as A
inner join st_jforxzc B on SUBSTRING(A.XZJD_DM,7,3)=B.zq_dm
) t
group by xzjd_mc

[解决办法]
select XZJD_MC, sum(B.jfxzc_mc),sum(B.JFXZC_MJ),sum(B.QX_DM),sum(B.zq_dm),sum(B.jfxzc_dm),
(select sum(tb_mj) from ST_DLTB where DL_DM= '111 ' and SZXZC_DM=JFXZC_MC group by JFXZC_MC)as e111,
(select sum(tb_mj) from ST_DLTB where DL_DM= '325 ' and SZXZC_DM=JFXZC_MC group by JFXZC_MC)as cw325
--into #ccc
from st_xzorjd as A
inner join st_jforxzc B on SUBSTRING(A.XZJD_DM,7,3)=B.zq_dm
group by xzjd_mc