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求随即产生N个随即字符解决办法

发布时间: 2012-01-07 21:41:55 作者: rapoo

求随即产生N个随即字符
public static char[] constant = {
'0','1','2','3','4','5','6','7','8','9',
'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z',
'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'
};

public static string GetRandomStringByLength(int Length)
{
StringBuilder newRandom = new StringBuilder();

Random rd = new Random(unchecked((int)DateTime.Now.Ticks));

for (int i = 0; i < Length; i++)
{
newRandom.Append(constant[rd.Next(0,62)]);
}

return newRandom.ToString();
}


比如产生11个
for (int i = 0; i < 11; i++)
{
GetRandomStringByLength(10)+"<br/>";
}

我这么做 都是重复的 为什么呢?
请高人指点!!

[解决办法]

C# code
public static string GenerateRandom(int Length){    StringBuilder builder = new StringBuilder(0x3e);    Random random = new Random();    for (int i = 0; i < Length; i++)    {        builder.Append(constant[random.Next(0x3e)]);    }    return builder.ToString();} 

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