DataGrid 绑定 xml 的有关问题

DataGrid 绑定 xml 的问题
XmlDocument dom = new XmlDocument();
dom.LoadXml(usersxml);
dom.Save( "d:/userxml.xml ");
dom.RemoveAll();
DataSet ds =new DataSet();
ds.ReadXml( "d:/userxml.xml ");
this.DataGrid1.DataSource = ds.Tables[0];
this.DataGrid1.DataBind();

什么都没读出来

其实只是想取得一列就行每个 <user> 里的 <param name= "realname " value= "陈立军 " /> 这个

也换了种写法可也没显示出数据求XDJM们帮帮忙看下~~~谢谢

XmlNodeList nodes = dom.SelectNodes( "orgUnit/user/param[@name= 'realname '] ");
if(nodes!=null)
{
foreach (XmlNode node in nodes)
{
DataTable dt = new DataTable();
dt.Columns.Add( "name ",Type.GetType( "System.String "));

dt.Columns.Add(node.Attributes[ "realname "].Value);
this.DataGrid1.DataSource=dt;
this.DataGrid1.DataBind();
}

---------------------
上面的程序也显示不出数据~~~

下面是我的XML格式及内容

<?xml version= "1.0 " encoding= "UTF-8 "?>
<orgUnit id= "2 " name= "办公室 ">
<user>
<param name= "category " value= " " />
<param name= "createdate " value= "2007-3-28 " />
<param name= "email " value= "clj@jsppd.gov.cn " />
<param name= "mobile " value= "1234567890 " />
<param name= "orgid " value= "2 " />
<param name= "orgname " value= " " />
<param name= "otherway " value= "1234567890 " />
<param name= "password " value= "666 " />
<param name= "phone " value= " " />
<param name= "position " value= "主任 " />
<param name= "realname " value= "陈立军 " />
<param name= "registerdate " value= "2007-3-28 " />
<param name= "servicedate " value= "2018-10-11 " />
<param name= "status " value= "N " />
<param name= "type " value= "01 " />
<param name= "userdsc " value= "陈立军 " />
<param name= "userid " value= "135 " />
<param name= "username " value= "clj@jsppd.gov.cn " />
</user>
<user>

<param name= "status " value= "N " />
<param name= "type " value= "01 " />
<param name= "userdsc " value= "周伟 " />
<param name= "userid " value= "29 " />
<param name= "username " value= "zw@jsppd.gov.cn " />
</user>
<user>
<param name= "category " value= " " />
<param name= "createdate " value= "2007-3-28 " />
<param name= "email " value= "zxm@jsppd.gov.cn " />
<param name= "mobile " value= " " />
<param name= "orgid " value= "2 " />
<param name= "orgname " value= " " />
<param name= "otherway " value= " " />
<param name= "password " value= "666 " />
<param name= "phone " value= " " />
<param name= "position " value= " " />
<param name= "realname " value= "张笑梅 " />
<param name= "registerdate " value= "2007-3-28 " />
<param name= "servicedate " value= "2018-10-11 " />
<param name= "status " value= "N " />
<param name= "type " value= "01 " />
<param name= "userdsc " value= "张笑梅 " />
<param name= "userid " value= "30 " />
<param name= "username " value= "zxm@jsppd.gov.cn " />
</user>
</orgUnit>

分不够再加请帮帮忙~~~

[解决办法]
this.DataGrid1.DataSource = ds.Tables[0].DateView;

[解决办法]
你取出XML已经到DataSet中了，可以直接用DataTable的Select方法查找出你要的数据，再绑定不就行了。
[解决办法]
第二种的写法不对，应该是：

XmlNodeList nodes = dom.SelectNodes( "orgUnit/user/param[@name= 'realname '] ");
if (nodes != null)
{
DataTable dt = new DataTable();
dt.Columns.Add( "name ", Type.GetType( "System.String "));
foreach (XmlNode node in nodes)
{
DataRow row = dt.NewRow();
row[ "name "] = node.Attributes[ "value "].Value;

dt.Rows.Add(row);

}
this.GridView1.DataSource = dt;
this.GridView1.DataBind();
}

DataGrid 绑定 xml 的有关问题

热点推荐