在.net中用c#开发程序，播放声音问题，请知道赐教！
我的播放声音的代码如下：
[System.Flags]
public enum PlaySoundFlags : int
{
SND_SYNC = 0x0000,
SND_ASYNC = 0x0001,
SND_NODEFAULT = 0x0002,
SND_LOOP = 0x0008,
SND_NOSTOP = 0x0010,
SND_NOWAIT = 0x00002000,
SND_FILENAME = 0x00020000,
SND_RESOURCE = 0x00040004
}
[System.Runtime.InteropServices.DllImport( "CoreDll.DLL ", EntryPoint = "PlaySound ", SetLastError = true)]
private static extern bool PlaySound(string szSound, System.IntPtr hMod, PlaySoundFlags flags);
private void PlaySuccess()
{
PlaySound( "bbb.wav ", new System.IntPtr(), PlaySoundFlags.SND_SYNC);
}
private void PlayUnsuccess()
{
PlaySound( "aaa.wav ", new System.IntPtr(), PlaySoundFlags.SND_SYNC);
}

问题是，如何只用文件名就能够播放，我现在必须要加入全路径才能播放。这个问题是不是和资源有关系？如果有关系的话，怎么添加编译，调用资源？

[解决办法]
//有标准类就用标类，尽量别用API
//参考如下代码
private void button1_Click(object sender, EventArgs e)
{
SoundPlayer sndPing = new SoundPlayer(); // using System.Media;
sndPing.Stream = Properties.Resources.MySound;
sndPing.Play();
}
[解决办法]
打开

解决方案
ApplicationName
Properties
Resources.resx

添加资源
添加现有文件

[解决办法]
try..

private void playSoundFromResource()
{
SoundPlayer sndPing = new SoundPlayer(SoundRes.GetType(), "Ping.wav ");
sndPing.Play();
}
[解决办法]
我的调试环境是2005
你可以参考liujia_0421的代码 //MSDN里Copy出来的
[解决办法]
TO:我的调试环境是2005
你可以参考liujia_0421的代码 //MSDN里Copy出来的

呵呵,被你看出来了...
[解决办法]
呵呵，我也拷贝了那段代码
但发现编译通不过
所以改了改，变量名都没变哈
[解决办法]
我在2003上调试,通过了.
代码如下:

[System.Flags]
public enum PlaySoundFlags : int
{
SND_SYNC = 0x0000,
SND_ASYNC = 0x0001,
SND_NODEFAULT = 0x0002,
SND_LOOP = 0x0008,
SND_NOSTOP = 0x0010,
SND_NOWAIT = 0x00002000,
SND_FILENAME = 0x00020000,
SND_RESOURCE = 0x00040004
}
[System.Runtime.InteropServices.DllImport( "CoreDll.DLL ", EntryPoint = "PlaySound ", SetLastError = true)]
private static extern bool PlaySound(string szSound, System.IntPtr hMod, PlaySoundFlags flags);
public const int SND_FILENAME = 0x00020000;
public const int SND_ASYNC = 0x0001;


private void button1_Click(object sender, System.EventArgs e)
{
try
{
PlaySound( "\\My Documents\\train.wav ", new System.IntPtr(), PlaySoundFlags.SND_SYNC);
}
catch(System.Exception ex)
{
MessageBox.Show(ex.Message, "Error Message ");
}