How can i convert a 8 bytes array into datetime?
How can i convert a 8 bytes array into datetime?

The 8 bytes array was read from a binary file written by delphi .

i read the array into an array and try to convert it to datetime.

But i was fail.

i had try this


long testLong = BitConverter.ToInt64(hexString,0);
DateTime dt = new DateTime(testLong);


and this


double doub = BitConverter.ToDouble(hexString, 0);
long testLong = BitConverter.DoubleToInt64Bits(doub);
DateTime dt = new DateTime(testLong);

they both faild to give me the right things....

What should i do???








[解决办法]
string s1 = Encoding.Default.GetString(b);
DateTime t ;
DateTime.TryParse(s1,out t);

[解决办法]
贼烂的英语。。。中国人就用中文了贝

还i was fail ... ...

如果Delphi写入到文件中的是datetime的字符表达，就用c#转回来，用DateTime.Parse()解析。
如果是DateTime的long形式。就new DateTime(long)
[解决办法]
object tmpObj;
BinaryFormatter formatter = new BinaryFormatter();
Stream stream = File.OpenRead(path);
tmpObj = formatter.Deserialize(stream);
stream.Close();
convert.toDateTime(tmpObj);
上面是我从文本留里读数据不知道可不可以