请问：判断JToggleButton的select状态设置不同背景色有关问题

请教：判断JToggleButton的select状态设置不同背景色问题
想实现一个效果：JToggleButton，当没按下去时显示绿色，按下去时显示黄色。
但不知为什么按下去后显示不出黄色来，而是默认的灰色。
请教各位高手，这是什么原因？以及要达到这个目的应该如何做！
非常感谢各位高手，有提示也欢迎，谢谢！
代码如下：

Java code

package test24Buttons;import java.awt.Color;import java.awt.event.ActionEvent;import java.awt.event.ActionListener;import javax.swing.JFrame;import javax.swing.JPanel;import javax.swing.JToggleButton;public class Hour {    JPanel timePanel = new JPanel();    JBusyTimeButton btn1 = new JBusyTimeButton("1");    JBusyTimeButton btn2 = new JBusyTimeButton("2");    JBusyTimeButton btn3 = new JBusyTimeButton("3");    JBusyTimeButton btn4 = new JBusyTimeButton("4");    JBusyTimeButton btn5 = new JBusyTimeButton("5");    JBusyTimeButton btn6 = new JBusyTimeButton("6");        public Hour() {        timePanel.add(btn1);        timePanel.add(btn2);        timePanel.add(btn3);        timePanel.add(btn4);        timePanel.add(btn5);        timePanel.add(btn6);    }        public JPanel getBusyTimePanel() {        return timePanel;    }        public class JBusyTimeButton extends JToggleButton {        private static final long serialVersionUID = 1L;                public JBusyTimeButton(String text) {            super(text);            setBackground(Color.green);            this.addActionListener(new ActionListener() {                public void actionPerformed(ActionEvent e) {                    if (!((JToggleButton)e.getSource()).getModel().isSelected()) {                        ((JToggleButton)e.getSource()).setBackground(Color.green);                    } else {                        ((JToggleButton)e.getSource()).setBackground(Color.yellow);                    }                }            });        }    }        public static void main(String[] args) {        JFrame frame = new JFrame();        Hour bt = new Hour();        frame.add(bt.getBusyTimePanel());        frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);        frame.pack();        frame.setLocationRelativeTo(null);        frame.setVisible(true);        }}

[解决办法]
我改了一下第一次按下是灰色的，第二次点击是黄色背景，我也不是很清楚为什么出现这个效果
发现如果设置前景色的话一切会是按照逻辑走

Java code

import java.awt.Color;import java.awt.event.ActionEvent;import java.awt.event.ActionListener;import javax.swing.*;public class Hour {    JPanel timePanel = new JPanel();    JBusyTimeButton btn1 = new JBusyTimeButton("1");    JBusyTimeButton btn2 = new JBusyTimeButton("2");    JBusyTimeButton btn3 = new JBusyTimeButton("3");    JBusyTimeButton btn4 = new JBusyTimeButton("4");    JBusyTimeButton btn5 = new JBusyTimeButton("5");    JBusyTimeButton btn6 = new JBusyTimeButton("6");    public Hour() {        timePanel.add(btn1);        timePanel.add(btn2);        timePanel.add(btn3);        timePanel.add(btn4);        timePanel.add(btn5);        timePanel.add(btn6);    }    public JPanel getBusyTimePanel() {        return timePanel;    }    public class JBusyTimeButton extends JToggleButton {        private static final long serialVersionUID = 1L;        public JBusyTimeButton(String text) {            super(text);            setBackground(Color.green);            this.addActionListener(new ActionListener() {                public void actionPerformed(ActionEvent e) {//                    if (!((JToggleButton)e.getSource()).isSelected()) {//                        ((JToggleButton)e.getSource()).setBackground(Color.green);//                    } else {//                        ((JToggleButton)e.getSource()).setBackground(Color.YELLOW);//                    }                    JToggleButton j=(JToggleButton)e.getSource();                    ButtonModel bm=j.getModel();                    if(bm.isSelected()) {                        j.setBackground(Color.YELLOW);                        System.out.println("奇数次按下，更改颜色");                    }                }            });        }    }    public static void main(String[] args) {        JFrame frame = new JFrame();        Hour bt = new Hour();        frame.add(bt.getBusyTimePanel());        frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);        frame.pack();        frame.setLocationRelativeTo(null);        frame.setVisible(true);    }} 
 
[解决办法]
我做实验的时候也是猜到了是执行了setBackgroud的方法，但是因为多线程的机制没有及时重绘按钮
不过也没整清楚怎么改，另一方面，我用前景色设置逻辑上都是很正常的。

我觉得能满足需求的情况下，用按钮的Icon来解决是不错的选择，给你贴出来代码，代码里面获取image的方法不推荐，虽然可以跑
Java codepublic JBusyTimeButton(String text) {            super(text);            setBackground(Color.green);            this.addActionListener(new ActionListener() {                public void actionPerformed(ActionEvent e) {                    JToggleButton j=(JToggleButton)e.getSource();                    ButtonModel bm=j.getModel();                    if(bm.isSelected()) {//                        j.setBackground(Color.YELLOW);                        //这里找一张跟按钮恰好大小的图片就可以了                          j.setIcon(new ImageIcon("resources/images/thu2.jpeg"));                        System.out.println("奇数次按下，更改颜色");                    } else{                         j.setIcon(null);                    }                }            });
[解决办法]
Java code    public class JBusyTimeButton extends JToggleButton {        private static final long serialVersionUID = 3243445422431L;        public JBusyTimeButton(String text) {            super(text);            setBackground(Color.GREEN);            this.addActionListener(new ActionListener() {                    public void actionPerformed(ActionEvent e) {                        JToggleButton toggle = (JToggleButton)e.getSource();                        if(toggle.isSelected()) {                            toggle.setBackground(Color.YELLOW);                        }else {                            toggle.setBackground(Color.GREEN);                        }                    }                });        }    }
[解决办法]

很，代码证明你这个根本不会变成黄色背景色一次……

楼主还是用Icon的方法解决吧，可以参照我写的那个例子

探讨
Java code
    public class JBusyTimeButton extends JToggleButton {
        private static final long serialVersionUID = 3243445422431L;

        public JBusyTimeButton(String text) {
            ……

[解决办法]
  public class JBusyTimeButton extends JToggleButton {
       private static final long serialVersionUID = 3243445422431L;

       public JBusyTimeButton(String text) {
           super(text);
           setBackground(Color.GREEN);
           this.addActionListener(new ActionListener() {
                   public void actionPerformed(ActionEvent e) {
                       JToggleButton toggle = (JToggleButton)e.getSource();

                       if(toggle.isSelected()) {
                           toggle.setBackground(Color.YELLOW);
                       }else {
                           toggle.setBackground(Color.GREEN);
                       }
                   }
               });
       }
   }

[解决办法]
探讨
java -version
java version "1.7.0"
Java(TM) SE Runtime Environment (build 1.7.0-b147)
Java HotSpot(TM) Client VM (build 21.0-b17, mixed mode, sharing)

[解决办法]
楼上的方法可以啊！牛人，学习

请问：判断JToggleButton的select状态

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