请问如何接受Post方法传过来的数据
我要做一个页面test.aspx用来接收这个函数提交的数据如何实现？
private void SendWebRequest()
{
string msgid, srcid, destid, content;
msgid = "1 ";
srcid = "2 ";
destid = "3 ";
content = "4 ";
string reqData = @ " <?xml version= " "1.0 " " encoding= " "GB2312 " "?>
<submit_sms>
<cp_id> ##CPID## </cp_id>
<cp_msg_id> ##MSGID## </cp_msg_id>
<SrcTermId> ##SRCID## </SrcTermId>
<DestTermId> ##DESTID## </DestTermId>
<FeeType> 101 </FeeType>
<content> <![CDATA[##Content##]]> </content>
</submit_sms>
";
reqData = reqData.Replace( "##CPID## ", "7777 ");
reqData = reqData.Replace( "##MSGID## ", msgid.ToString());
reqData = reqData.Replace( "##SRCID## ", srcid.ToString());
reqData = reqData.Replace( "##DESTID## ", destid.ToString());
reqData = reqData.Replace( "##Content## ", content.ToString());


HttpWebRequest req = (HttpWebRequest)WebRequest.Create( "http://127.0.0.1:1673/Sms/test.aspx ");
req.Method = "POST ";
req.Accept = "*/* ";
req.UserAgent = "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; SV1; .NET CLR 1.1.4322) ";

req.Headers.Add( "ContentType ", "application/x-www-form-urlencoded ");
StreamWriter reqStm = new StreamWriter(req.GetRequestStream());
reqStm.Write(reqData);

HttpWebResponse rsp = (HttpWebResponse)req.GetResponse();
if (rsp.StatusCode != HttpStatusCode.OK)
{
//TODO:
}
else
{
StreamReader rspStm = new StreamReader(rsp.GetResponseStream(), Encoding.Default);

string retStr = rspStm.ReadToEnd();
XmlDocument xml;
try
{
xml = new XmlDocument();
}
catch (Exception ex)
{
//TODO:
return;
}
xml.LoadXml(retStr);
XmlNode n = xml.SelectSingleNode(@ "/submit_sms_resp/status/text() ");
int retValue = int.Parse(n.Value);
//retValue
}
}
结贴加分～～在线等

[解决办法]
Request.InputStream;从输入流里面读
[解决办法]
如果你输入的流是XML的话
System.Xml.XmlDocument doc = new System.Xml.XmlDocument(); doc.Load(Request.InputStream);
[解决办法]
Request[ "XXX "]!
[解决办法]
不要使用 Request[...]，那会取到 post数据以外的其它数据。使用：Request.Form[...]。
[解决办法]
。。。速度啊，呵呵。
接你分等下说你倒分。