解决问题马上给分，在线等！
高手帮我改一下下面的代码，当第一次运行时不要跳出警告框，当按了浏览器的刷新健是才弹出，解决马上给分，在线等！
<HEAD>
<SCRIPT LANGUAGE= "JavaScript ">
<!-- Begin
var expDays = 1; // number of days the cookie should last
function GetCookie (name) {
var arg = name + "= ";
var alen = arg.length;
var clen = document.cookie.length;
var i = 0;
while (i < clen) {
var j = i + alen;
if (document.cookie.substring(i, j) == arg)
return getCookieVal (j);
i = document.cookie.indexOf( " ", i) + 1;
if (i == 0) break;
}
return null;
}
function SetCookie (name, value) {
var argv = SetCookie.arguments;
var argc = SetCookie.arguments.length;
var expires = (argc > 2) ? argv[2] : null;
var path = (argc > 3) ? argv[3] : null;
var domain = (argc > 4) ? argv[4] : null;
var secure = (argc > 5) ? argv[5] : false;
document.cookie = name + "= " + escape (value) +
((expires == null) ? " " : ( "; expires= " + expires.toGMTString())) +
((path == null) ? " " : ( "; path= " + path)) +
((domain == null) ? " " : ( "; domain= " + domain)) +
((secure == true) ? "; secure " : " ");
}
function DeleteCookie (name) {
var exp = new Date();
exp.setTime (exp.getTime() - 1);
var cval = GetCookie (name);
document.cookie = name + "= " + cval + "; expires= " + exp.toGMTString();
}
var exp = new Date();
exp.setTime(exp.getTime() + (expDays*24*60*60*1000));
function amt(){
var count = GetCookie( 'count ')
if(count == null) {
SetCookie( 'count ', '1 ')
return 1
}
else {
var newcount = parseInt(count) + 1;
DeleteCookie( 'count ')
SetCookie( 'count ',newcount,exp)
return count
}
}
function getCookieVal(offset) {
var endstr = document.cookie.indexOf ( "; ", offset);
if (endstr == -1)
endstr = document.cookie.length;
return unescape(document.cookie.substring(offset, endstr));
}
function checkCount() {
var count = GetCookie( 'count ');
if (count == null) {
count=1;
SetCookie( 'count ', count, exp);
alert( "只有一次。 ");
}
else {
count++;
SetCookie( 'count ', count, exp);
}
}
// End -->
</script>
<BODY OnLoad= "checkCount() ">
[解决办法]
在session里作个标志吧，打开页面时检查session中是否有该标志，没有新增，有就表示非首次打开。