高手请进，关于Socket 接受多播数据包的问题？
最近用C#中的Socket进行通讯编码。
但是发现在用Socket进行接受组播的时候，因为组播地址不是本地的127.0.0.1所以无法绑定。接受不料组播数据包。
代码如下：

IPEndPoint ipEndPoint = new IPEndPoint(System.Net.IPAddress.Parse(multiIPAddress), mutilUdpPort);
udpReceiveMutilVideoSocket = new Socket(System.Net.Sockets.AddressFamily.InterNetwork, System.Net.Sockets.SocketType.Dgram, System.Net.Sockets.ProtocolType.Udp);
udpReceiveMutilVideoSocket.Bind(ipEndPoint);

在Bind的时候，告诉我说，远程主机地址无法绑定。

我也想过用UdpClient，但是UdpClient没有延时设置，如果万一给组播地址发送组播数据包的机器挂了，我这个UdpClient不是一直在那里等待接受数据包吗？这样下来，程序就down在那里啦！

哪位用过用Socket进行接受组播数据包的，指点下啊，谢谢！本人学习C#不到10天啊，大家帮帮忙啊，项目紧急啊，必须尽快解决啦！没有办法啦！



[解决办法]
using System;
using System.Net;
using System.Net.Sockets;
using System.Threading;

namespace UDPReceiver
{
public delegate void OnReceiveEventHandler(string xmlPack);

/// <summary>
/// MultiCast 的摘要说明。
/// </summary>
public class MultiCast
{
private string addr;
private int port;
private UdpClient subscriber;
private bool bShutDown = true;
private Thread thReceive;

/// <summary>
/// 数据到达事件
/// </summary>
public event OnReceiveEventHandler OnReceive;

/// <summary>
/// 构造
/// </summary>
/// <param name= "multiCastIP "> 组播IP </param>
/// <param name= "udpPort "> 端口 </param>
public MultiCast(string multiCastIP,int udpPort)
{
addr = multiCastIP;
port = udpPort;
OnReceive += new OnReceiveEventHandler(MultiCast_OnReceive);
}

/// <summary>
/// 启动监听
/// </summary>
public void Startup()
{
if (!bShutDown)
return;

subscriber = new UdpClient(port);
IPAddress ipMultiCast = IPAddress.Parse(addr);

try
{
subscriber.JoinMulticastGroup(ipMultiCast);
}
catch(Exception ex)
{
System.Windows.Forms.MessageBox.Show( "无法加入到多播组[ " + addr + "]\n\n " + ex.ToString());
return;
}

//抛出监听线程
bShutDown = false;
thReceive = new Thread(new ThreadStart(Receive));
thReceive.Start();
}

/// <summary>
/// 关闭监听
/// </summary>
public void ShutDown()
{
bShutDown = true;
thReceive.Join(500);

try
{
thReceive.Abort();
}
catch
{

}

subscriber.Close();
subscriber = null;
}

private void MultiCast_OnReceive(string xmlPack)

{
//do nothing
}


private void Receive()
{
byte[] bytes = null;
IPEndPoint ipFrom = null;
string xml = " ";

while(!bShutDown)
{
bytes = subscriber.Receive(ref ipFrom);

if (bytes != null)
{
if (bytes.Length > 0)
{
xml = System.Text.ASCIIEncoding.ASCII.GetString(bytes);
//激发事件
OnReceive(xml);
}
}
}
}
}
}

[解决办法]
好像可以的样子，以前有做过

还是留名看一下
[解决办法]
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