关于minus 求助!
假设有2张表A,B
A表有
NAME NO
DC 1
DW 2
DF 3
B表有
NAME NO
DC 1
DZ 6
DS 7

我要找出A表中没有的完整数据
select B_NAME_NAME from B minus select A_NAME from A ;
这样查出来的是
NAME
DZ
DS
但是我想查出的是B表在A表中没有的全部数据
请问如何写?




[解决办法]
是这样子的吗？

SQL code

 
 SQL> create table a(name nvarchar2(30),no int); 
  
 Table created 
  
 SQL> create table b(name nvarchar2(30),no int); 
  
 Table created 
  
 SQL>  
 SQL> insert into a 
 2  select 'dc',1 from dual union select 'dw',2 from dual union select 'df',3 from dual; 
  
 3 rows inserted 
  
 SQL> insert into b 
 2  select 'dc',1 from dual union select 'dz',6 from dual union select 'ds',7 from dual; 
  
 3 rows inserted 
  
 SQL> select * from a; 
  
 NAME                                                NO 
 ------------------------ --------------------------------------- 
 dc                                                 1 
 df                                                 3 
 dw                                                 2 
  
 SQL> select * from b; 
  
 NAME                                                NO 
 ------------------------ --------------------------------------- 
 dc                                                 1 
 ds                                                 7 
 dz                                                 6 
  
 SQL> select * from b where not exists(select 1 from a where a.name=b.name); 
  
 NAME                                                NO 
 ------------------------ --------------------------------------- 
 ds                                                 7 
 dz                                                 6 
  
 SQL>  
  
 

[解决办法]
6楼的就可以了，还可以用外连接实现。

select b.* from b left outer join a
on b.name = a.name
where a.name is null;
[解决办法]
是的.已经想到了
selec * from b
where b.b_name in
( select B_NAME from B minus select A_NAME from A )

------------------
LZ这样简直是多此一举！
既然你要用minus，还不如这样呢：
select * from B
minus
select * from A