TreeView中选择父级checkbox时,子级连动
function SelectChild()
{
var obj = event.srcElement;
if(obj.type == "checkbox")
{
do
{
obj = obj.parentElement;
}
while(obj.tagName != "TABLE");
CheckedInput(obj.nextSibling,event.srcElement.checked);
}
}

//选择Div(父节点)内所有input
function CheckedInput(obj,t)
{
var tbs = obj.getElementsByTagName("TABLE");
var i,l;
for(i = 0 , l = tbs.length ; i < l ; ++i)
{
tbs[i].rows(0).cells(2).childNodes[0].checked = t;
}
}

[解决办法]

JScript code

function SelectCheckBox()    {        var ele = event.srcElement;        //单击节点上的CheckBox获取所有子节点        if(ele.type=='checkbox')         {            var childrenDivID = ele.id.replace('CheckBox','Nodes');            var div = document.getElementById(childrenDivID);            if(div!=null)             {                var checkBoxs = div.getElementsByTagName('INPUT');                for(var i=0;i<checkBoxs.length;i++)                 {          if(checkBoxs[i].type=='checkbox')          {            checkBoxs[i].checked=ele.checked;                  }                }             }          }    }