两张关联表,如何显示一条记录,sql如何写?
表a
id,name
1 a
2 c

表b (fid与表a的id关联)

id fid,n1,n2,b1(bit型)
1 1 aa bb 0
2 1 cc dd 1
3 1 ee ff 1
4 2 ss xx 0
5 2 yy zz 0


要显示如下形式

a.id a.name,b.n1,b.n2
1 a ee ff
2 c yy zz

也就是 全显示出表A中记录,然后在b表中找出b1为1(没有就是0),id最大的一条记录与之相连形成一条记录显示

如何写sql?先谢了



[解决办法]

SQL code

--按某一字段分组取最大(小)值所在行的数据--2007-10-23于杭州/*数据如下：name val memoa    2   a2(a的第二个值)a    1   a1--a的第一个值a    3   a3:a的第三个值b    1   b1--b的第一个值b    3   b3:b的第三个值b    2   b2b2b2b2b    4   b4b4b    5   b5b5b5b5b5*/--创建表并插入数据：create table tb(name varchar(10),val int,memo varchar(20))insert into tb values('a',    2,   'a2(a的第二个值)')insert into tb values('a',    1,   'a1--a的第一个值')insert into tb values('a',    3,   'a3:a的第三个值')insert into tb values('b',    1,   'b1--b的第一个值')insert into tb values('b',    3,   'b3:b的第三个值')insert into tb values('b',    2,   'b2b2b2b2')insert into tb values('b',    4,   'b4b4')insert into tb values('b',    5,   'b5b5b5b5b5')go--一、按name分组取val最大的值所在行的数据。--方法1：select a.* from tb a where val = (select max(val) from tb where name = a.name) order by a.name--方法2：select a.* from tb a where not exists(select 1 from tb where name = a.name and val > a.val)--方法3：select a.* from tb a,(select name,max(val) val from tb group by name) b where a.name = b.name and a.val = b.val order by a.name--方法4：select a.* from tb a inner join (select name , max(val) val from tb group by name) b on a.name = b.name and a.val = b.val order by a.name--方法5select a.* from tb a where 1 > (select count(*) from tb where name = a.name and val > a.val ) order by a.name/*name       val         memo                 ---------- ----------- -------------------- a          3           a3:a的第三个值b          5           b5b5b5b5b5*/--二、按name分组取val最小的值所在行的数据。--方法1：select a.* from tb a where val = (select min(val) from tb where name = a.name) order by a.name--方法2：select a.* from tb a where not exists(select 1 from tb where name = a.name and val < a.val)--方法3：select a.* from tb a,(select name,min(val) val from tb group by name) b where a.name = b.name and a.val = b.val order by a.name--方法4：select a.* from tb a inner join (select name , min(val) val from tb group by name) b on a.name = b.name and a.val = b.val order by a.name--方法5select a.* from tb a where 1 > (select count(*) from tb where name = a.name and val < a.val) order by a.name/*name       val         memo                 ---------- ----------- -------------------- a          1           a1--a的第一个值b          1           b1--b的第一个值*/--三、按name分组取第一次出现的行所在的数据。select a.* from tb a where val = (select top 1 val from tb where name = a.name) order by a.name/*name       val         memo                 ---------- ----------- -------------------- a          2           a2(a的第二个值)b          1           b1--b的第一个值*/--四、按name分组随机取一条数据。select a.* from tb a where val = (select top 1 val from tb where name = a.name order by newid()) order by a.name/*name       val         memo                 ---------- ----------- -------------------- a          1           a1--a的第一个值b          5           b5b5b5b5b5*/--五、按name分组取最小的两个(N个)valselect a.* from tb a where 2 > (select count(*) from tb where name = a.name and val < a.val ) order by a.name,a.valselect a.* from tb a where val in (select top 2 val from tb where name=a.name order by val) order by a.name,a.valselect a.* from tb a where exists (select count(*) from tb where name = a.name and val < a.val having Count(*) < 2) order by a.name/*name       val         memo                 ---------- ----------- -------------------- a          1           a1--a的第一个值a          2           a2(a的第二个值)b          1           b1--b的第一个值b          2           b2b2b2b2*/--六、按name分组取最大的两个(N个)valselect a.* from tb a where 2 > (select count(*) from tb where name = a.name and val > a.val ) order by a.name,a.valselect a.* from tb a where val in (select top 2 val from tb where name=a.name order by val desc) order by a.name,a.valselect a.* from tb a where exists (select count(*) from tb where name = a.name and val > a.val having Count(*) < 2) order by a.name/*name       val         memo                 ---------- ----------- -------------------- a          2           a2(a的第二个值)a          3           a3:a的第三个值b          4           b4b4b          5           b5b5b5b5b5*/ 
 
[解决办法]
SQL code
select a.* , isnull(t.n1,'') n1,isnull(t.n2,'') n2 from a left join(select t.* from b where id = (select max(id) from tb where fid = t.fid)) ton a.id = t.fid
[解决办法]
SQL code
select t1.*,t2.n1,t2.n2 from  a t1left join(select * from b a where not exists(select 1 from b where a.fid=fid and id>a.id))t2on t1.id=t2.fid
[解决办法]
SQL code
 
 create table A(id int,name varchar(10)) 
 insert into A select 1,'a' 
 insert into A select 2,'c' 
 insert into A select 3,'e' 
  
 create table B(id int identity(1,1),fid int,n1 varchar(10),n2 varchar(10),b1 bit) 
 insert into B select 1,'aa','bb',0 
 insert into B select 1,'cc','dd',1 
 insert into B select 1,'ee','ff',1  --this 
 insert into B select 2,'ss','xx',0 
 insert into B select 2,'yy','zz',0  --this 
 insert into B select 3,'gg','hh',0 
 insert into B select 3,'kk','jj',1  --this 
 insert into B select 3,'qq','ss',0 
  
  
 select A.id,A.name,AA.n1,AA.n2 
 from A 
 left join 
 ( 
 select t1.* 
 from B t1 
 inner join 
 ( 
 select fid,max(id) as id 
 from B 
 where (exists(select 1 from B x where x.fid=B.fid and x.b1=1) and b1=1) 
  Or (not exists(select 1 from B y where y.fid=B.fid and y.b1=1) and b1=0) 
 group by fid 
 ) t2 
 on t1.id=t2.id 
 ) AA 
 on A.id=AA.fid 
  
 /* 
 id      name     n1     n2      
 ----------- ---------- ---------- ----------  
 1       a      ee     ff 
 2       c      yy     zz 
 3       e      kk     jj 
 */ 
  
  
 drop table A,B