java Arc2D问题求助
请问下用Arc2D.Double(double x, double y, double w, double h, double start, double extent, int type) 中的w,h是外围矩形的长和宽嘛？那若已知的是一条圆弧的起始点，起始角度，终止角度，和半径，怎么来求w,h那？
先谢过各位。

[解决办法]
w - 完整椭圆的总宽度，此弧是该椭圆的一部分。
h - 完整椭圆的总高度，此弧是该椭圆的一部分。

如果你知道半径了,那么w,h就是他们的2倍.(-_-!直径)
要是圆弧,相等就是了...

a sample:

Java code

import java.awt.*;import java.awt.geom.*;import javax.swing.*;public class Test73 {    public static void main(String[] args) {        // TODO Auto-generated method stub        JFrame frame = new DrawFrame();        frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);        frame.setVisible(true);    }}class DrawFrame extends JFrame {    public DrawFrame() {        // TODO Auto-generated constructor stub        setTitle("DrawArc");        setSize(200, 200);        add(new DrawPanel());    }}class DrawPanel extends JPanel {    public void paintComponent(Graphics g) {        super.paintComponent(g);        Graphics2D g2 = (Graphics2D) g;            g2.draw(new Arc2D.Double(40, 50, 100, 50, 0, 60, Arc2D.OPEN));        g2.draw(new Arc2D.Double(40, 50, 100, 50, 120, 60, Arc2D.OPEN));        g2.draw(new Arc2D.Double(40, 50, 100, 50, 240, 60, Arc2D.OPEN));                /*g2.draw(new Arc2D.Double(40, 50, 100, 50, 0, 60, Arc2D.PIE));        g2.draw(new Arc2D.Double(40, 50, 100, 50, 120, 60, Arc2D.PIE));        g2.draw(new Arc2D.Double(40, 50, 100, 50, 240, 60, Arc2D.PIE));*/    }}