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switch case 和 level = Math.Log10(a

发布时间: 2012-02-03 22:02:47 作者: rapoo

switch case 和 level = Math.Log10(amount);有问题
using System;
using System.Collections.Generic;
using System.Text;

namespace Test1_19
{
class Program
{
static void Main(string[] args)
{
Int32 amount, cost, level;
Console.WriteLine("请输入购买教科书的数量:\n");
amount = Int32.Parse(Console.ReadLine());
cost = amount * 25;
level = Math.Log10(amount);
switch(level)
{
case (level>1&&level<10):
cost *=0.9;
break;

case (level>100&&level<1000):
cost*=0.85;
break;
case (level>1000):
cost*=0.8;
break;
default :cost=cost;
break;
}
Console.WriteLine("费用:\n,{0}",cost);


}
}
}


[解决办法]

C# code
            cost  = amount * 25;             level = (int)Math.Log10(amount);             switch(level)             {                 case 0:          // 表示:   1 ≤ amount < 10                    break;                 case 1:          // 表示:  10 ≤ amount < 100                    cost *= 0.9;                     break;                 case 2:          // 表示: 100 ≤ amount < 1000                    cost *= 0.85;                     break;                 default:          // 表示: 其他情形,也就是 amount ≥ 1000 或 amount < 1                    cost *= 0.8;                     break;             } 

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