C#读写文本 送分啊!快进来抢分
这是我文本内容:
1234 43 54 23 554 231 4541
1232 423 514 354 31 441 1
1231 243 154 123 54 31 454
这些数据他们之间都是一个空格隔开的
我要将这些数据 不满足4位的在他前面不空格 让他满足4位

用C#代码怎么实现 请指教!


[解决办法]
先把文本取出来,用Regex.Split(...)来得到你的分开的数组String[]，然后循环foreach来判断是否是4位数，
不足的补上就可以了。
[解决办法]

C# code

 
       try 
       { 
         StreamReader sr = new StreamReader("test.txt"); 
         StringBuilder sb = new StringBuilder(); 
         while (!sr.EndOfStream) 
         { 
           string str = sr.ReadLine(); 
           string[] temp = str.Split(' '); 
           for (int i = 0; i  < temp.Length; i++) 
           { 
             if (temp[i].Length != 4) 
               temp[i] = temp[i].PadLeft(4, ' '); 
           } 
           str = string.Join(" ", temp); 
           sb.Append(str + "\n"); 
         } 
         sr.Close(); 
         string[] result = sb.ToString().Split("\n".ToCharArray()); 
         StreamWriter sw = new StreamWriter("test.txt", false); 
         foreach (string s in result) 
           sw.WriteLine(s); 
         sw.Close(); 
       } 
       catch (Exception e) 
       { 
         Console.WriteLine(e.Message); 
       } 
 

C# code

StreamReader sr = new StreamReader(@"D:\1.txt");using (StreamWriter sw = new StreamWriter(@"D:\2.txt", true)){    while (sr.Peek() != -1)    {        string[] temp = sr.ReadLine().Split(' ');        for (int i = 0; i < temp.Length; i++)            temp[i] = temp[i].PadLeft(4, ' ');        string s = string.Join(" ", temp);        sw.WriteLine(s);    }}sr.Close();