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SQL合并语句

发布时间: 2012-02-03 22:02:47 作者: rapoo

求一个SQL合并语句,急,
在数据表中有如下内容
name odrer
ASD D
ASD G
ASD J
DFG D
DRT K
现在想得到另一个数据表如下
name1 odrer1
ASD D,G,J
DFG D
DRT K
也就是相同的NAME在一行显示,后面跟上ORDER的值,谢谢!

[解决办法]
用函数的,抄一个给你~~~

--测试数据
create table csdn(id int,txt varchar(10))
insert csdn
select 1, 'a ' union all
select 1, 'b ' union all
select 1, 'c ' union all
select 2, 'aa ' union all
select 2, 'bb ' union all
select 2, 'cc ' union all
select 3, 'aaa ' union all
select 3, 'bbb '
select * from csdn
go

create function Gettxt(@id int)
returns varchar(8000)
as
begin
declare @s varchar(8000)
set @s= ' '
select @s=@s + ', ' +txt from csdn where id=@id
--return @s
return stuff(@s,1,1, ' ')
end
go

select id,dbo.Gettxt(id) txt from csdn group by id
go

drop function Gettxt
drop table csdn
go
[解决办法]
eg:

Create Table TEST
(aaa Int,
bbbb Int,
amount Int)
Insert TEST Select 111, 222, 333
Union All Select 222, 222, 444
Union All Select 111, 333, 555
Union All Select 111, 222, 777
GO
Create Function Getamount(@aaa Int, @bbbb Int)
Returns Varchar(8000)
As
Begin
Declare @S Varchar(8000)
Select @S = ' '
Select @S = @S + ', ' + Rtrim(amount) From TEST Where aaa = @aaa And bbbb = @bbbb
Select @S = Stuff(@S , 1, 1 , ' ')
Return @S
End
GO
Select
aaa,
bbbb,
dbo.Getamount(aaa, bbbb) As amount
From
TEST
Group By aaa, bbbb
GO
Drop Table TEST
Drop Function Getamount
--Result
/*
aaa bbbb amount
111 222 333,777
111 333 555
222 222 444
*/
[解决办法]
--带符号合并行列转换

--有表t,其数据如下:
a b
1 1
1 2
1 3
2 1
2 2
3 1
--如何转换成如下结果:
a b
1 1,2,3
2 1,2
3 1

create table tb
(
a int,
b int
)
insert into tb(a,b) values(1,1)
insert into tb(a,b) values(1,2)
insert into tb(a,b) values(1,3)
insert into tb(a,b) values(2,1)
insert into tb(a,b) values(2,2)
insert into tb(a,b) values(3,1)
go

if object_id( 'pubs..f_hb ') is not null
drop function f_hb
go

--创建一个合并的函数
create function f_hb(@a int)
returns varchar(8000)
as
begin
declare @str varchar(8000)
set @str = ' '
select @str = @str + ', ' + cast(b as varchar) from tb where a = @a
set @str = right(@str , len(@str) - 1)
return(@str)
End
go

--调用自定义函数得到结果:
select distinct a ,dbo.f_hb(a) as b from tb

drop table tb

--结果
a b
----------- ------
1 1,2,3


2 1,2
3 1

(所影响的行数为 3 行)


多个前列的合并
数据的原始状态如下:
ID PR CON OP SC
001 p c 差 6
001 p c 好 2
001 p c 一般 4
002 w e 差 8
002 w e 好 7
002 w e 一般 1
===========================
用SQL语句实现,变成如下的数据
ID PR CON OPS
001 p c 差(6),好(2),一般(4)
002 w e 差(8),好(7),一般(1)

if object_id( 'pubs..tb ') is not null
drop table tb
go

create table tb
(
id varchar(10),
pr varchar(10),
con varchar(10),
op varchar(10),
sc int
)

insert into tb(ID,PR,CON,OP,SC) values( '001 ', 'p ', 'c ', '差 ', 6)
insert into tb(ID,PR,CON,OP,SC) values( '001 ', 'p ', 'c ', '好 ', 2)
insert into tb(ID,PR,CON,OP,SC) values( '001 ', 'p ', 'c ', '一般 ', 4)
insert into tb(ID,PR,CON,OP,SC) values( '002 ', 'w ', 'e ', '差 ', 8)
insert into tb(ID,PR,CON,OP,SC) values( '002 ', 'w ', 'e ', '好 ', 7)
insert into tb(ID,PR,CON,OP,SC) values( '002 ', 'w ', 'e ', '一般 ', 1)
go

if object_id( 'pubs..test ') is not null
drop table test
go
select ID,PR,CON , OPS = op + '( ' + cast(sc as varchar(10)) + ') ' into test from tb

--创建一个合并的函数
if object_id( 'pubs..f_hb ') is not null
drop function f_hb
go
create function f_hb(@id varchar(10),@pr varchar(10),@con varchar(10))
returns varchar(8000)
as
begin
declare @str varchar(8000)
set @str = ' '
select @str = @str + ', ' + cast(OPS as varchar) from test where id = @id and @pr = pr and @con = con
set @str = right(@str , len(@str) - 1)
return(@str)
End
go

--调用自定义函数得到结果:
select distinct id ,pr , con , dbo.f_hb(id,pr,con) as OPS from test

drop table tb
drop table test

--结果
id pr con OPS
---------- ---------- ---------- -------------------
001 p c 差(6),好(2),一般(4)
002 w e 差(8),好(7),一般(1)

(所影响的行数为 2 行)


create table b
(col varchar(20))

insert b values ( 'a ')
insert b values ( 'b ')
insert b values ( 'c ')
insert b values ( 'd ')
insert b values ( 'e ')


declare @sql varchar(1024)
set @sql= ' '
select @sql=@sql+b.col+ ', ' from (select col from b) as b
set @sql= 'select ' ' '+@sql+ ' ' ' '
exec(@sql)

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