大家帮我看一下这段代码吧
# include "stdio.h "
# include "conio.h "

void shi();
void cal();

main()
{char c;

do
{
printf( "****************************************\n\n\n\n ");
printf( " 1. Calcullator\n ");
printf( " 2. Biao da shi\n ");
printf( "\n\n\n\n****************************************\n ");
printf( "\n\n\n\n\n\nplease input you choice the number:\n ");
c=getchar();
if(c== '1 ')cal();
if(c== '2 ')shi();
printf( "please choice the number again\n ");
}while(c!= '1 '&&c!= '2 ');
}


大家帮我看一下这段代码吧，我有点不明白中间的
printf( "****************************************\n\n\n\n ");
printf( " 1. Calcullator\n ");
printf( " 2. Biao da shi\n ");
printf( "\n\n\n\n****************************************\n ");
printf( "\n\n\n\n\n\nplease input you choice the number:\n ");

这段是干什么的

printf( "****************************************\n\n\n\n ");
printf( " 1. Calcullator\n ");
printf( " 2. Biao da shi\n ");
printf( "\n\n\n\n****************************************\n ");

这四句去掉行吗

[解决办法]
printf( "****************************************\n\n\n\n "); //这是输出一排星号
printf( " 1. Calcullator\n "); //为的是美观,没什么用
printf( " 2. Biao da shi\n ");
printf( "\n\n\n\n****************************************\n ");
printf( "\n\n\n\n\n\nplease input you choice the number:\n "); //这输出一堆回车
//再输出一句话,用来提示用户如何操作
这段是干什么的

printf( "****************************************\n\n\n\n "); //这都是个美观的作用
printf( " 1. Calcullator\n "); //楼主完全可以删之
printf( " 2. Biao da shi\n ");
printf( "\n\n\n\n****************************************\n ");