求教 用C++编一个程序
用C++编一个程序
题目是这样的:
编一个程序能把名片上所有的信息都保存到一个文件上,并且能通过名片上的""公司名和"姓名"查找到文件中名片的所有的信息.
请各位大虾帮帮忙!先谢了!!!

[解决办法]
这个可以从文件中读出名片并搜索. 名片只有公司名和人名信息

C/C++ code

#include <iostream>#include <fstream>#include <iterator>#include <list>#include <string>#include <algorithm>using namespace std;struct Card{    string CompanyName;    string Name;};istream& operator >>(istream& in, Card& c){    in>>c.CompanyName>>c.Name;    return in;}ostream& operator <<(ostream& out, const Card& c){    out<<c.CompanyName<<' '<<c.Name;    return out;}class CardCmp{public:    enum COMPTYPE {COMPANY, PERSON};    CardCmp(const string& s, COMPTYPE type = COMPANY):        strName(s),cmpType(type) {}    bool operator ()(const Card& c)    {        return (cmpType == COMPANY)?            (strName == c.CompanyName) : (strName == c.Name);    }private:    string strName;    COMPTYPE cmpType;};void card(){    list<Card> lstCard;    list<Card>::iterator pos;    fstream fs("card.txt");    istream_iterator<Card> ifs_iter(fs);    istream_iterator<Card> ifs_end;    copy(ifs_iter, ifs_end, back_inserter(lstCard));    for (pos = lstCard.begin(); pos != lstCard.end(); ++pos)    {        cout<<*pos<<endl;    }    string s;    cout<<"Please inpu company name:\n";    cin>>s;    pos = find_if(lstCard.begin(), lstCard.end(), CardCmp(s));    if (pos != lstCard.end())    {        cout<<"founded :"<<*pos<<endl;    }    else    {        cout<<"not found"<<endl;    }    cout<<"Please inpu company name:\n";    cin>>s;    pos = find_if(lstCard.begin(), lstCard.end(),        CardCmp(s, CardCmp::PERSON));    if (pos != lstCard.end())    {        cout<<"founded :"<<*pos<<endl;    }    else    {        cout<<"not found"<<endl;    }    fs.close();}