boost_thread库求教
小弟最近在研究boost thread库
下面是自己写的1个基本的多线程处理事务的模型 跑是基本没问题 但是不懂效率上来讲 合理么
先谢谢各位了

C/C++ code

#include <iostream>#include <boost/thread.hpp>#include <boost/bind.hpp>#include <list>using namespace std;boost::mutex mutex;class ThreadMgr{public:    ThreadMgr(int i)         : m_work_flag(true),m_thread_num(i)    {        m_works.clear();        Start();    }    ~ThreadMgr()     {        m_thread_list.join_all();    }    void Stop()    {        m_work_flag = false;    }    void AddWork(int i)    {        m_works.push_back(i);    }private:    void Start()    {        for (int i = 0; i < m_thread_num; ++i)        {            boost::thread* work = new boost::thread(boost::bind(&ThreadMgr::CallThread, this));            m_thread_list.add_thread(work);        }    }    void CallThread()    {        while (m_work_flag)        {            int i = 0;            // 这里对m_work_flag的判断是为了在关闭按钮触发后及时停止后台的线程            while(m_work_flag && GetWork(i))            {                boost::unique_lock<boost::mutex> lock(mutex);                 cout << "thread[" << boost::this_thread::get_id() << "] is doing work[" << i << "]." << endl;            }        }    }    bool GetWork(int& i)    {        boost::unique_lock<boost::mutex> lock(mutex);         if (m_works.empty())        {            return false;        }        i = m_works.front();        m_works.pop_front();        return true;    }    boost::thread_group    m_thread_list;    list<int> m_works;    bool m_work_flag;    int m_thread_num;};int main(){    ThreadMgr* tm = new ThreadMgr(4);    for (int i = 1; i < 10; ++i)    {        tm->AddWork(i);    }    for (int i = 10; i < 20; ++i)    {        tm->AddWork(i);    }    tm->Stop();    // 关闭按钮之类的触发    delete tm;    return 0;}

[解决办法]
队列本身就应该封装成线程安全的，在外层控制不好，并且你外层控制的不对

C/C++ code

void AddWork(int i)    {        m_works.push_back(i);    }