一个含有分隔符的字符串，如何拆分后逐条插入到表中，内详，马上结贴
例如这样一个字符串1&30~10353&32~
"~ "代表一条记录， "& "代表字段值
有多少个不确定，就是说不一定就是两条
就是拆分后插入到表中
拆分后
insert into SYS_User_Role ( ROLE_ID,DEPARTMENT_ID ) values ( 1,30 )
insert into SYS_User_Role ( ROLE_ID,DEPARTMENT_ID ) values ( 10353,32 )

[解决办法]
create table SYS_User_Role(ROLE_ID int,DEPARTMENT_ID int)
go

create procedure sp_test(@str varchar(8000))
as
begin
declare @n_str varchar(50)
while charindex( '~ ',@str)> 0
begin
set @n_str=replace(left(@str,charindex( '~ ',@str)-1), '& ', ', ')
set @str=stuff(@str,1,charindex( '~ ',@str), ' ')
exec( 'insert into SYS_User_Role(ROLE_ID,DEPARTMENT_ID) values( '+@n_str+ ') ')
end
end
go

exec sp_test '1&30~10353&32~ '
go

select * from SYS_User_Role
/*
ROLE_ID DEPARTMENT_ID
----------- -------------
1 30
10353 32
*/
go

drop procedure sp_test
drop table SYS_User_Role
go
[解决办法]



declare @s varchar(30)
set @s= '1&30~10353&32~ '

if right(@s,1)= '~ '
set @s=left(@s,len(@s)-1)

declare @sql varchar(300)

set @sql= 'insert into SYS_User_Role select '+replace(replace(@s, '& ', ', '), '~ ', ' union all select ')

print @sql

exec(@sql)

[解决办法]


if exists (select * from dbo.sysobjects where id = object_id(N '[dbo].[f_splitSTR] ') and xtype in (N 'FN ', N 'IF ', N 'TF '))
drop function [dbo].[f_splitSTR]
GO

--使用临时性分拆辅助表法
CREATE FUNCTION f_splitSTR(
@s varchar(8000), --待分拆的字符串
@split varchar(10) --数据分隔符
)RETURNS @re TABLE(col varchar(100))
AS
BEGIN
--创建分拆处理的辅助表(用户定义函数中只能操作表变量)
DECLARE @t TABLE(ID int IDENTITY,b bit)
INSERT @t(b) SELECT TOP 8000 0 FROM syscolumns a,syscolumns b

INSERT @re SELECT SUBSTRING(@s,ID,CHARINDEX(@split,@s+@split,ID)-ID)
FROM @t
WHERE ID <=LEN(@s+ 'a ')
AND CHARINDEX(@split,@split+@s,ID)=ID
RETURN
END
GO
declare @str varchar(8000)
set @str = '1&30~10353&32~ '
create table SYS_User_Role(ROLE_ID int,DEPARTMENT_ID int)
insert SYS_User_Role
select left(col,charindex( '& ',col)-1),right(col,len(col)-charindex( '& ',col)) from f_splitSTR(@str, '~ ') where charindex( '& ',col) > 0
select * from SYS_User_Role
go
drop table SYS_User_Role

/*

ROLE_ID DEPARTMENT_ID
----------- -------------
1 30
10353 32

(2 row(s) affected)
*/
[解决办法]
如果个数不确定的话,最好是在程序中写.
使用循环,先找~,然后再找&
[解决办法]
使用StringTokenizer tok = new StringTokenizer(spec, "~ ");进行两次操作,
第一次取出行数据即:1&30和10353&32等等
第二次取出列数据1,30;10353,32;并插入数据库inset into talbe_name values(1,30)
------解决方案--------------------

declare @str varchar(800) 21
set @str = 1&30~10353&32~
set @str = repalce (replace(@str, '& ', ' ' ', ' ' '), '~ ', ' ' 'union all select ' ' ')
set @str = 'select ' ' ' + @str
set @str = reverse(stuff(reverse(@str),1,19, ' '))
insert into SYS_User_Role ( ROLE_ID,DEPARTMENT_ID )
exec(@str)

[解决办法]
declare @str varchar(8000)
set @str = 1&30~10353&32~
set @str = repalce (replace(@str, '& ', ' ' ', ' ' '), '~ ', ' ' 'union all select ' ' ')
set @str = 'select ' ' ' + @str
set @str = reverse(stuff(reverse(@str),1,19, ' '))
insert into SYS_User_Role ( ROLE_ID,DEPARTMENT_ID )
exec(@str)
[解决办法]
declare @str varchar(100), @sql varchar(1000)
select @str = '1&30~10353&32~ '
while charindex( '~ ', @str) <> 0
begin
print 'insert into SYS_User_Role ( ROLE_ID,DEPARTMENT_ID ) values ( ' + left(@str, charindex( '& ', @str) - 1) + ', ' + substring(@str, charindex( '& ', @str) + 1, charindex( '~ ', @str) - charindex( '& ', @str) - 1) + ') '
set @str = right(@str, len(@str) - charindex( '~ ', @str))
end