回车事件
有两个表单，两个按扭。
如果我写完第一个点回车，触发第一个按扭事件
写第二个文本，点回车，触发第二个按扭事件。
请问这样该怎么写啊。
[解决办法]
- C# code
private void Form1_KeyPress(object sender, KeyPressEventArgs e) { if((int)e.KeyChar ==13){ button1.PerformClick(); } }
[解决办法]
- HTML code
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"><html><head> <title>Untitled</title></head><Script type = "text/javascript" >window.document.onkeydown = keyword;function keyword(){ if (event.keyCode==13) { if(document.form1.txtName1.value.replace(/(^\s*)/g, "") != "" && document.form1.txtName2.value.replace(/(^\s*)/g, "") == "") { enter(1); }else if(document.form1.txtName2.value.replace(/(^\s*)/g, "") != "" && document.form1.txtName1.value.replace(/(^\s*)/g, "") == "") { enter(2); }else if(document.form1.txtName1.value.replace(/(^\s*)/g, "") != "" && document.form1.txtName2.value.replace(/(^\s*)/g, "") != "") { enter(1); enter(2); } else{ document.form1.txtName1.value = ""; document.form1.txtName2.value = ""; alert("空"); } }}function enter(i){ document.getElementById("btnSearch" +i).click();} </Script><body ><form name = "form1" ><table> <tr> <td> <input type = "text" name = "txtName1" width = "85px" height = "20px" > </td> <td> <input type = "button" name = "btnSearch1" width = "85px" height = "20px" onclick = "alert('aaa');"> </td> <td> <input type = "text" name = "txtName2" width = "85px" height = "20px"> </td> <td> <input type = "button" name = "btnSearch2" width = "85px" height = "20px" onclick = "alert('bbb');"> </td> </tr></table></body></html>
[解决办法]
标准解决方案：
<asp:Panel ID="Panel1" runat="server" DefaultButton="Button1" >
<asp:TextBox ID="TextBox1" runat="server"></asp:TextBox>
<asp:Button ID="Button1" runat="server" Text="Button" /></asp:Panel>
<br />
<asp:Panel ID="Panel2" runat="server" DefaultButton="Button2" >
<asp:TextBox ID="TextBox2" runat="server"></asp:TextBox>
<asp:Button ID="Button2" runat="server" Text="Button" /></asp:Panel>