malloc的问题，死了死了
typedef struct node{
int data;
struct node *next;
}Node;

Node **path;
int *pathLength；

path=(struct node **)malloc(N * sizeof(struct node*)）


pathLength=(int *)malloc(N* sizeof(int))

void push_path(int x,int f)
{
Node *newNode;

newNode = (Node*)malloc(sizeof(Node))

newNode-> data = f;
newNode-> next = path[x-1];
path[x-1] = newNode;

pathLength[x-1]++;
}


int pop_path (int x)
{
Node *deleteNode = NULL;
int f;
if (path[x-1] != NULL)
{
deleteNode = path[x-1];
f = deleteNode-> data;
path[x-1] = deleteNode-> next;
free(deleteNode);
deleteNode = NULL;

pathLength[x-1]--;

return f;
}
else
return 0;
}


现在想将path[w]复制给path[w],做法如下，重新给path[u]分配空间，长度是path[w]的长度及pathLength[w]，可发现malloc之后，path[u]后面只分配了一个Node啊？后果就是memcpy以后，path[u]和path[w]后面的地址一样了？请问问题到底在哪儿啊？不甚感激～


free(path[u]);
path[u] = NULL;

path[u-1] = (Node*)malloc(pathLength[w-1]*sizeof(struct node*))

path[u-1] = memcpy(path[u-1],path[w-1],pathLength[w-1]*sizeof(struct node*))

pathLength[u-1] = pathLength[w-1];




[解决办法]
free(path[u]);
path[u] = NULL;

path[u] = (Node**)malloc(pathLength[w]*sizeof(struct node*))

path[u] = memcpy(path[u],path[w],pathLength[w]*sizeof(struct node*))

pathLength[u] = pathLength[w];
[解决办法]
path[u-1] = (Node*)malloc(pathLength[w-1]*sizeof(struct node*))

path[u-1] = memcpy(path[u-1],path[w-1],pathLength[w-1]*sizeof(struct node*))

pathLength[u-1] = pathLength[w-1];

改成对 path[u] 的操作 ～