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高分求一存储过程解决思路

发布时间: 2012-02-12 17:16:33 作者: rapoo

高分求一存储过程
ALTER PROCEDURE db_owner.edittzsm
@uid int
AS
declare @sql varchar(500)

if exists (select * from userlicai where uid=@uid and DATEDIFF(d,[date],DATEADD(hh,6,getdate()))=0)
begin
set @sql=insert into userlicai(uid,[date]) values(@uid,DATEADD(hh,6,getdate()))
if DATEPART(ww,DATEADD(hh,6,getdate()))=7
set @sql=insert into userlicai(uid,[date]) values(@uid,DATEADD(hh,54,getdate()))
if DATEPART(ww,DATEADD(hh,6,getdate()))=1
begin
if not exists(select * from userlicai where uid=@uid and DATEDIFF(d,[date],DATEADD(hh,30,getdate()))=0)
set @sql=insert into userlicai(uid,[date]) values(@uid,DATEADD(hh,30,getdate()))
end
end
exec @sql


总是报错,请高手帮帮忙!

[解决办法]
ALTER PROCEDURE db_owner.edittzsm
@uid int
AS
declare @sql varchar(500)

if exists (select * from userlicai where uid=@uid and DATEDIFF(d,[date],DATEADD(hh,6,getdate()))=0)
begin
set @sql= 'insert into userlicai(uid,[date]) values( '+rtrim(@uid)+ ',DATEADD(hh,6,getdate())) '
if DATEPART(ww,DATEADD(hh,6,getdate()))=7
set @sql= 'insert into userlicai(uid,[date]) values( '+rtrim(@uid)+ ',DATEADD(hh,54,getdate())) '
if DATEPART(ww,DATEADD(hh,6,getdate()))=1
begin
if not exists(select * from userlicai where uid=@uid and DATEDIFF(d,[date],DATEADD(hh,30,getdate()))=0)
set @sql= 'insert into userlicai(uid,[date]) values( '+rtrim(@uid)+ ',DATEADD(hh,30,getdate())) '
end
end
exec @sql
[解决办法]
ALTER PROCEDURE db_owner.edittzsm
@uid int
AS
declare @sql varchar(500)

if exists (select * from userlicai where uid=@uid and DATEDIFF(d,[date],DATEADD(hh,6,getdate()))=0)
begin
set @sql= 'insert into userlicai(uid,[date]) values( '+cast(@uid as varchar)+ ', ' ' '+cast(DATEADD(hh,6,getdate()) as varchar)+ ' ' ') '
if DATEPART(ww,DATEADD(hh,6,getdate()))=7
set @sql= 'insert into userlicai(uid,[date]) values( '+cast(@uid as varchar)+ ', ' ' '+cast(DATEADD(hh,54,getdate()) as varchar)+ ' ' ') '
if DATEPART(ww,DATEADD(hh,6,getdate()))=1
begin
if not exists(select * from userlicai where uid=@uid and DATEDIFF(d,[date],DATEADD(hh,30,getdate()))=0)
set @sql= 'insert into userlicai(uid,[date]) values( '+cast(@uid as varchar)+ ', ' ' '+cast(DATEADD(hh,30,getdate()) as varchar)+ ' ' ') '


end
end
exec @sql
[解决办法]
在SQL语句中,字符串应该用单引号括起来!
[解决办法]
对于你的题目,首先很抱歉你没有给出你这个存储过程的主要用途,所以很难给你改,不过可以给你提几个建议:
1.你的问题主要出现在字符串没有用单引号括起来.
2.if exists语句不要用select *,用select 1这样效率会高很多.
3.不知道你的if else语句中有多少个sql语句要运行,如果要运行多个的话请在给sql变量赋值之后立刻执行exec语句.
[解决办法]

动态sql语句基本语法
1 :普通SQL语句可以用Exec执行

eg: Select * from tableName
Exec( 'select * from tableName ')
Exec sp_executesql N 'select * from tableName ' -- 请注意字符串前一定要加N

2:字段名,表名,数据库名之类作为变量时,必须用动态SQL

eg:
declare @fname varchar(20)
set @fname = 'FiledName '
Select @fname from tableName -- 错误,不会提示错误,但结果为固定值FiledName,并非所要。
Exec( 'select ' + @fname + ' from tableName ') -- 请注意 加号前后的 单引号的边上加空格

当然将字符串改成变量的形式也可
declare @fname varchar(20)
set @fname = 'FiledName ' --设置字段名

declare @s varchar(1000)
set @s = 'select ' + @fname + ' from tableName '
Exec(@s) -- 成功
exec sp_executesql @s -- 此句会报错


declare @s Nvarchar(1000) -- 注意此处改为nvarchar(1000)
set @s = 'select ' + @fname + ' from tableName '
Exec(@s) -- 成功
exec sp_executesql @s -- 此句正确

3. 输出参数
declare @num int,
@sqls nvarchar(4000)
set @sqls= 'select count(*) from tableName '
exec(@sqls)
--如何将exec执行结果放入变量中?

declare @num int,
@sqls nvarchar(4000)
set @sqls= 'select @a=count(*) from tableName '
exec sp_executesql @sqls,N '@a int output ',@num output
select @num


[解决办法]
ALTER PROCEDURE db_owner.edittzsm
@uid int
AS
declare @sql varchar(1000)

if exists (select * from userlicai where uid=@uid and DATEDIFF(d,[date],DATEADD(hh,6,getdate()))=0)
begin
set set @sql= 'insert into userlicai(uid,[date]) values( '+rtrim(@uid)+ ', '+quotename(dateadd(hh,6,getdate()), ' ' ' ')+ ') '
if DATEPART(ww,DATEADD(hh,6,getdate()))=7
set set @sql=@sql+ ' insert into userlicai(uid,[date]) values( '+rtrim(@uid)+ ', '+quotename(DATEADD(hh,54,getdate()), ' ' ' ')+ ') '
if DATEPART(ww,DATEADD(hh,6,getdate()))=1
begin
if not exists(select * from userlicai where uid=@uid and DATEDIFF(d,[date],DATEADD(hh,30,getdate()))=0)
set @sql=@sql+ ' insert into userlicai(uid,[date]) values( '+rtrim(@uid)+ ', '+quotename(DATEADD(hh,30,getdate()), ' ' ' ')+ ') '
end
end
exec @sql

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