关于继承中的构造函数调用问题..
代码如下:

#include "iostream "
using namespace std;
class A
{
public:
A(){cout < < "this A " < <endl;}
A(int x,int s){k=x;q=s;cout < < "this is a(int x) " < <endl;}
private:
int k;
int q;
};
class B:public A
{
public:
B(){cout < < "this is B " < <endl;}
B(int i,int j):A(1,2)
{ aa=i;bb=j;
cout < < "aa " < <aa < <endl < < "bb " < <bb < <endl;
}
private:
int aa;
int bb;

};
main()
{
B (2,3);

return 0;
}
按道理说,应该先调用基类的构造函数，输出 "this is A ",然后在输出 "this is a(int x),最后是aa=..bb=..
但在机器上运行后得到:
this is a(int x)
aa2
bb3

怎么最后运算确是这个结果?



[解决办法]
B (2,3)==>
B(int i,int j):A(1,2)
===> A(int x,int s){k=x;q=s;cout < < "this is a(int x) " < <endl;}

[解决办法]
楼主，你要看调用的是哪个构造函数，带参数的构造函数，B(int i,int j):A(1,2) ，这个就不会调用默认构造函数（无参构造函数）了
[解决办法]
同意楼上
如果你定义一个对象 B b;
则会先调用A(){cout < < "this A " < <endl;}然后 B(){cout < < "this is B " < <endl;}