菜鸟求救：我的程序怎么总益出？
我的程序很简单，就是用一个指针来读取一个3X4的数组中的数据，可在运行search函数时，总是报错 益出，而aver函数就没问题，大家看一下把！
main()
{float aver(float *p,int n);
float search(float (*p)[4],int n);
float score[3][4]={{67,65,70,60},{80,87,90,81},{90,99,100,98}};
aver(score[0],12);
search(score,n);
}
float aver(float *p,int n)
{float*p_end;
float sum=0,aver;
p_end=p+n-1;
for(;p <=p_end;p++)
{sum=sum+(*p);}
aver=sum/n;
printf( "average is %f\n ",aver);
}
float search(float (*p)[4],int n)
{int i;
printf( "the score of No.%d is : ",n);
for(i=0;i <4;i++)printf( "%.2f ",*(*(p+n)+i));
}
对了，我用的是TC

[解决办法]
float aver(float *p,int n);
float search(float (*p)[4],int n);
int main(void)
{


float score[3][4]={{67,65,70,60},{80,87,90,81},{90,99,100,98}};
aver(score[0],12);
search(score,1);//这里原来是N,最好改成数字,
return 0;
}
float aver(float *p,int n)
{
float*p_end;
float sum=0,aver;
p_end=p+n-1;
for(;p <=p_end;p++)
{
sum=sum+(*p);
}
aver=sum/n;
printf( "average is %f\n ",aver);
return 0;
}
float search(float (*p)[4],int n)
{
int i;
printf( "the score of No.%d is : ",n);
for(i=0;i <4;i++)
{
printf( "%.2f\n ",*(*(p+n)+i));

}
return 0;
}