为什么调用不了函数
程序简单:
#include <iostream.h>
typedef unsigned short int ushort;

int k(ushort i,ushort j)
{

return i/j;
}
void main()
{
ushort i ,j;
cout < < "enter two number: " < <endl;
cout < < "number one: ";
cin> > i;
cout < < "number two: ";
cin> > j;

k(i, j);

cout < < "answer: " < <k < <endl;
}

我试过debug了,程序居然没有调用k;
我用了别的程序以同样的方法编,如下:
#include <iostream.h>
long fib(int n)

{
long s;
if(n==1||n==2)
return 1;
s=fib(n-1)+fib(n-2);
return s;
}
void main()
{
int n;

cout < < "请输入一个整数： ";
cin> > n;
fib(n);
cout < <fib(n) < <endl;


}

结果能调用fib,为什么啊~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

[解决办法]
cout < < "answer: " < <k < <endl;//k是地址，改成如下没问题：

int ret;
ushort i ,j;
cout < < "enter two number: " < <endl;
cout < < "number one: ";
cin> > i;
cout < < "number two: ";
cin> > j;

ret=k(i, j);

cout < < "answer: " < <ret < <endl;
[解决办法]
//k(i,j);
cout < < "answer: " < <k(i,j) < <endl;