页面传入ID，打开后怎么让下拉菜单的值显示为selected
如果这个ID和下拉菜单的某一个选项的值相同，打开页面时下拉菜单默认显示的是这个选项，
请问用JS怎么做？
如:ID=5
<form name= "form1 " method= "post " action= " ">
<select name= "select ">
<option value= "5 " selected> gf </option> //因为ID和选项的值相同就显示为：selected
<option value= "4 " > wq </option>
<option value= "2 " > we </option>
<option value= "3 " > sd </option>
<option value= "1 " > fd </option>
</select>
</form>
[解决办法]
<script>
function show()
{
var sel=document.getElementById( "select ");
var id=3;
sel.selectedIndex=id;
}
</script>
<body onload= "show(); ">
<form name= "form1 " method= "post " action= " ">
<select name= "select ">
<option value= "5 " selected> gf </option> //因为ID和选项的值相同就显示为：selected
<option value= "4 " > wq </option>
<option value= "2 " > we </option>
<option value= "3 " > sd </option>
<option value= "1 " > fd </option>
</select>
</form>
</body>