关于字符串指针和数组的问题
这个如何才能编译过？ 请大家帮忙看看

include <stdio.h>
include <stdlib.h>

int main()
{
typedef struct _S_VALUE{
char var[8+1];
char val[100+1];
}S_VALUE;
char sz[50]={0};

strcpy(sz,"abc");
S_VALUE ar[2] = {
"01",sz,
"",""};
return 0;
}


[解决办法]

C/C++ code

#include <stdio.h>#include <stdlib.h>#include <string.h>int main(){    typedef struct _S_VALUE{        char var[8+1];        char val[100+1];    }S_VALUE;    char sz[50]={0};        strcpy(sz,"abc");    S_VALUE ar[2] = {"01","abc","",""};          return 0;}
[解决办法]
类型不同，这样也行：
S_VALUE ar[2];

strncpy(ar[0].var,sz,sizeof(ar[0].var));
strncpy(ar[0].val,sz,sizeof(ar[0].val));

//........

[解决办法]
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
   typedef struct _S_VALUE{
       char var[8+1];
       char val[100+1];
   }S_VALUE;
   char sz[50]={0};
  
   strcpy(sz,"abc");
   S_VALUE ar[2] = {{"01","abc"},{"",""}}; 
       return 0;
}

你也可以尝试使用其他方法对结构体变量进行赋值，比如使用ar[0].var, ar[0].val等等吧。
[解决办法]
C/C++ code
#include <stdio.h>#include <stdlib.h>#include <string.h>int main(){  typedef struct _S_VALUE{  char var[8+1];  char val[100+1];  }S_VALUE;  char sz[50]={0};      strcpy(sz,"abc");  S_VALUE ar[2] = {{"01",sz},{"",""}};     return 0;}
[解决办法]
int main()
{
typedef struct _S_VALUE{
char var[8+1];
char val[100+1];
}S_VALUE;

//char sz[50]={0};

//strcpy(sz,"abc");
S_VALUE ar[2] = {
{"01","abc"},
{"",""}
}; 
}
[解决办法]
C/C++ code
#include <stdio.h>#include <stdlib.h>#include <string.h>int main(){  typedef struct _S_VALUE{  char var[8+1];  char *val;  }S_VALUE;  char sz[50]={"abc"};      //strcpy(sz,"abc");  S_VALUE ar[2] = {{"01",sz}, {"0","1"}};      //for test  printf("%s %s\n", ar[0].val, ar[0].var);  printf("%s %s\n", ar[1].val, ar[1].var);  return 0;}