java小题，求解
从键盘输入一个整数（1~20）
则以该数字为矩阵的大小，把1,2,3…n*n 的数字按照顺时针螺旋的形式填入其中。例如：
输入数字2，则程序输出：
1 2
4 3
输入数字3，则程序输出：
1 2 3
8 9 4
7 6 5
输入数字4， 则程序输出：
1 2 3 4
12 13 14 5
11 16 15 6
10 9 8 7


[解决办法]
http://blog.sina.com.cn/s/blog_7ea6850b0100qof0.html
[解决办法]

Java code

import java.io.BufferedReader;import java.io.IOException;import java.io.InputStreamReader;public class Test4 {    public static void main(String[] args) {    try {            int num = 1;            int cirCle[][] = new int[20][20];            int i, j, line, t;            System.out.println("请输入一个正整数");            InputStreamReader reader = new InputStreamReader(System.in);            BufferedReader input = new BufferedReader(reader);            String s = input.readLine();/* 执行输入流操作 */            int inputNum = Integer.parseInt(s);/* 加个int型的转换 */            System.out.println(inputNum);            line = inputNum;            for (t = 0; t < line; t++) {                for (i = t, j = t; j < inputNum - t; j++) { // 赋值上外围                    cirCle[i][j] = num;                    num++;                }                for (j = j - 1, i = i + 1; i < inputNum - t; i++) { // 赋值右外围                    cirCle[i][j] = num;                    num++;                }                for (j = j - 1, i = i - 1; j >= t; j--) { // 赋值下外围                    cirCle[i][j] = num;                    num++;                }                for (j = j + 1, i = i - 1; i > t; i--) { // 赋值左外围                    cirCle[i][j] = num;                    num++;                }            }                        for (int m = 0; m < line; m++) { // 输出结果                for (int n = 0; n < line; n++) {                    System.out.print(cirCle[m][n] + "\t");                }                System.out.println();            }        } catch (NumberFormatException e) {            e.printStackTrace();        } catch (IOException e) {            e.printStackTrace();        }    }}
[解决办法]
public class Test4 {
   public static void main(String[] args) {
   try {
           int num = 1;
           int cirCle[][] = new int[20][20];
           int i, j, line, t;
           System.out.println("请输入一个正整数");
           InputStreamReader reader = new InputStreamReader(System.in);
           BufferedReader input = new BufferedReader(reader);
           String s = input.readLine();/* 执行输入流操作 */
           int inputNum = Integer.parseInt(s);/* 加个int型的转换 */
           System.out.println(inputNum);
           line = inputNum;

           for (t = 0; t < line; t++) {
               for (i = t, j = t; j < inputNum - t; j++) { // 赋值上外围
                   cirCle[i][j] = num;
                   num++;
               }
               for (j = j - 1, i = i + 1; i < inputNum - t; i++) { // 赋值右外围
                   cirCle[i][j] = num;
                   num++;
               }
               for (j = j - 1, i = i - 1; j >= t; j--) { // 赋值下外围
                   cirCle[i][j] = num;
                   num++;
               }
               for (j = j + 1, i = i - 1; i > t; i--) { // 赋值左外围
                   cirCle[i][j] = num;
                   num++;
               }

           }
          
           for (int m = 0; m < line; m++) { // 输出结果
               for (int n = 0; n < line; n++) {
                   System.out.print(cirCle[m][n] + "\t");
               }
               System.out.println();
           } 
 
       } catch (NumberFormatException e) {
           e.printStackTrace();
       } catch (IOException e) {
           e.printStackTrace();
       }
   }
}