在ACCESS中如何使用IN /NOT IN,如果没有,有没有变通的方法
selet * from order where order_id in(select order_id from order_detail)


[解决办法]
--这句没有问题，只不过效率不是很高
selet * from [order] where order_id in (select order_id from order_detail)


--可以用表连接
selet A.*
from [order] A inner join order_detail b on A.order_id=B.order_id
[解决办法]
可以：
IN:
selet * from order where order_id in(select order_id from order_detail)
selet A.*
from [order] A inner join order_detail b on A.order_id=B.order_id
NOT IN:
selet * from order where order_id NOT in(select order_id from order_detail)
selet A.*
from [order] A LEFT join order_detail b on A.order_id=B.order_id WHERE ISNULL(B.order_id )