单链表就地逆转问题！！！有那位高手来帮下忙！！
#include<stdio.h>
#include<stdlib.h>
typedef struct LNode{
int data;
struct LNode *next;
}LNode,*LinkList;
void CreateList(LinkList &L,int n)
{
L=(LinkList)malloc(sizeof(LNode));
L->data=0;
L->next=NULL;
for(int i=n;i>0;--i)
{
LinkList p=(LinkList)malloc(sizeof(LNode));
printf("Input:\n");
scanf("%d",&p->data);
p->next=L->next;
L->next=p;



}


}
void main()
{
LinkList La,Lb,Lc;
CreateList(La,5);
Lb=La;
Lc=La->next;
while(Lc->next)
{
Lc->next->next=Lc;
Lc=Lc->next;

}
Lb->next->next=NULL;
Lb->next=Lc;
while(Lb->next)
{
printf("%d\n",Lb->data);
Lb=Lb->next;

}
}


[解决办法]

C/C++ code

#include <stdio.h>#include <stdlib.h>    typedef struct LNode{           int data;           struct LNode *next;  }LNode,*LinkList;    void CreateList(LinkList *L, int n)  {          int i;         LinkList p;         /*        *L = (LinkList)malloc(sizeof(LNode));           (*L)->data = 0;           (*L)->next = NULL;           */          *L = NULL;          for(i = n;i > 0;--i)           {                   p = (LinkList)malloc(sizeof(LNode));                   printf("Input:\n");                   scanf("%d", &p->data);                   p->next = (*L);                   (*L) = p;           }   }     int main(void)   {           LinkList La, Lb, Lc;           CreateList(&La, 5);           Lb = La;           Lc = NULL;           while(Lb != NULL)           {                   La = Lb->next;                  Lb->next = Lc;                  Lc = Lb;                  Lb = La;           }           //Lb->next->next = NULL;           Lb = Lc;           while(Lb != NULL)           {                   printf("%d\n", Lb->data);                   Lb = Lb->next;           }             return 0; }
[解决办法]
C/C++ code
LinkList * reverse(LinkList * L){    LinkList * L0;    if(L->next==NULL) return L;    L0 = reverse(L->next);    L0->next=L;    L->next=NULL;    return L0;}