XML值的
- XML code
<?xml version="1.0" standalone="yes" ?> <TestCase> <Case CaseID="Case001"> <User UserID="User001"> <FunctionName>FName1</FunctionName> <ActType>Create</ActType> <RequestNumber>3</RequestNumber> <FrequencyNumber>2</FrequencyNumber> <DelayNumber>1</DelayNumber> </User> <User UserID="User002"> <FunctionName>FName2</FunctionName> <ActType>Update</ActType> <RequestNumber>5</RequestNumber> <FrequencyNumber>2</FrequencyNumber> <DelayNumber>3</DelayNumber> </User> </Case> <Case CaseID="Case002"> <User UserID="User001"> <FunctionName>FName21</FunctionName> <ActType>Create</ActType> <RequestNumber>3</RequestNumber> <FrequencyNumber>2</FrequencyNumber> <DelayNumber>1</DelayNumber> </User> <User UserID="User002"> <FunctionName>FName22</FunctionName> <ActType>Update</ActType> <RequestNumber>5</RequestNumber> <FrequencyNumber>2</FrequencyNumber> <DelayNumber>3</DelayNumber> </User> </Case></TestCase>
要取得CaseID="Case001"且UserID="User002"的各元素的值如何做？
[解决办法]
XmlDocument doc = new XmlDocument();
doc.Load(@"D:\Project\C#Test\WindowsApplication1\WindowsApplication1\XMLFile1.xml");
XmlNodeList nodeList = doc.SelectNodes("//TestCase//Case[@CaseID='Case001']//User[@UserID='User002']//*");
List<string> values = new List<string>();
foreach (XmlElement element in nodeList)
{
if (!values.Contains(element.InnerText))
{
Debug.WriteLine(string.Format("ElementName:{0} Value:{1}",element.Name ,element.InnerText));
values.Add(element.InnerText);
}
}
[解决办法]
- JScript code
<html><head><script type="text/javascript" src="loadxmldoc.js"></script></head><body><script type="text/javascript">xmlDoc = loadXMLDoc("Xml1.xml");var nodeList = xmlDoc.selectNodes("//Case[@CaseID='Case001']//User[@UserID='User002']//*"); for(i=0;i<nodeList.length;i++){ alert(nodeList.item(i).nodeName+"-"+nodeList.item(i).childNodes[0].nodeValue);}</script></body></html>