不知道那里出错了，请帮我改下
#include <string>
#include <iostream>
using namespace std;

bool fibon_elem(int pos,int &elem)
{
if(pos<=0 || pos>1024)
{
elem = 0;
return false;
}
else
{
int elem = 0;
int n_1 =1,n_2 = 1;
for(int ix = 3;ix <=pos; ++ix)
{
elem = n_1 + n_2 ;
n_2 = n_1;
n_1 = elem;
}
}
return true;
}
int main()
{
int pos;
cout<<"请输入一个位置"<<endl;
cin>>pos;
int elem;
if(fibon_elem(pos,elem))
{
cout<<"element #"<<pos<<"is"<<elem<<endl;
}
else
{
cout <<"sorry,coudl not#"<<pos<<endl;
}
return 0;
}
// 1,1,2,3,5,8,13,21,34,55,89,144 我就是想实现类似这种
比如我输入POS为12，就直接显示144



[解决办法]
你应该在fibon_elem函数的for循环中直接输出菲薄那次数列。

[解决办法]
去掉int elem = 0;
的int
[解决办法]

C/C++ code

#include <string>#include <iostream>using namespace std;bool fibon_elem (int pos, int& elem){    if (pos <= 0 || pos > 1024)    {        elem = 0;        return false;    }    else    {        elem = 0;//mark,int去掉，要不然变量被覆盖        int n_1 = 1, n_2 = 1;        for (int ix = 3; ix <= pos; ++ix)        {            elem = n_1 + n_2 ;            n_2 = n_1;            n_1 = elem;        }    }    return true;}int main(){    int pos;    cout << "请输入一个位置" << endl;    cin >> pos;    int elem;    if (fibon_elem (pos, elem))    {        cout << "element #" << pos << "is" << elem << endl;    }    else    {        cout << "sorry,coudl not#" << pos << endl;    }    return 0;}