计算器程序，头文件和变量摆放位置不懂，求教
第一种是正确的
- C/C++ code
#include <stdio.h>#include <math.h>#define MAXOP 100#define NUMBER '0'int getop(char s[]);void push(double f);double pop();int main(){ int type; double op2; char s[MAXOP]; while ((type=getop(s)) != EOF) { switch (type) { case NUMBER: { push(atof(s)); break; } case '+': { push(pop() + pop()); break; } case '-': { op2 = pop(); push(pop() - op2); break; } case '*': { push(pop() * pop()); break; } case '/': { op2 = pop(); if (op2 != 0.0) { push(pop() / op2); } else { printf("error: zero divisor\n"); } break; } case '%': { op2 = pop(); if (op2 != 0.0) { push(fmod(pop(), op2)); } else { printf("error: zero divisor\n"); } break; } case '\n': { printf("\t%.8g\n", pop()); break; } default: { printf("error: unknown command %s\n", s); break; } } } return 0;}#define MAXVAL 100int sp=0;double val[MAXVAL];void push(double f){ if (sp < MAXVAL) { val[sp++] = f; } else { printf("error: stack full, can't push %g\n", f); }}double pop(){ if (sp > 0) { return val[--sp]; } else { printf("error: stack empty\n"); return 0.0; }}#include <ctype.h>#define MAXLINE 100int getline(char line[], int lim);int li=0;char line[MAXLINE];int getop(char s[]){ int c, i; if (line[li] == '\0') { if (getline(line, MAXLINE) == 0) { return EOF; } else { li = 0; } } while ((s[0]=c=line[li++]) == ' ' || c == '\t') { ; } s[1] = '\0'; if (!isdigit(c) && c!='.') { return c; } i = 0; if (isdigit(c)) { while (isdigit(s[++i] = c = line[li++])) { ; } } if (c == '.') { while (isdigit(s[++i] = c = line[li++])) { ; } } s[i] = '\0'; --li; return NUMBER;}int getline(char s[], int lim){ int c, i; i = 0; while (--lim>0 && (c=getchar())!=EOF && c!='\n') { s[i++] = c; } if (c == '\n') { s[i++] = c; } s[i] = '\0'; return i;}第二种编译通过，运行报错
- C/C++ code
#include <stdio.h>#include <math.h>#include <ctype.h>#define MAXLINE 100#define MAXOP 100#define MAXVAL 100#define NUMBER '0'int getline(char line[], int lim);int getop(char s[]);void push(double f);double pop();int main(){ int type; double op2; char s[MAXOP]; while ((type=getop(s)) != EOF) { switch (type) { case NUMBER: { push(atof(s)); break; } case '+': { push(pop() + pop()); break; } case '-': { op2 = pop(); push(pop() - op2); break; } case '*': { push(pop() * pop()); break; } case '/': { op2 = pop(); if (op2 != 0.0) { push(pop() / op2); } else { printf("error: zero divisor\n"); } break; } case '%': { op2 = pop(); if (op2 != 0.0) { push(fmod(pop(), op2)); } else { printf("error: zero divisor\n"); } break; } case '\n': { printf("\t%.8g\n", pop()); break; } default: { printf("error: unknown command %s\n", s); break; } } } return 0;}int getline(char s[], int lim){ int c, i; i = 0; while (--lim>0 && (c=getchar())!=EOF && c!='\n') { s[i++] = c; } if (c == '\n') { s[i++] = c; } s[i] = '\0'; return i;}int getop(char s[]){ int c, i, li; char line[MAXLINE]; li = 0; if (line[li] == '\0') { if (getline(line, MAXLINE) == 0) { return EOF; } else { li = 0; } } while ((s[0]=c=line[li++]) == ' ' || c == '\t') { ; } s[1] = '\0'; if (!isdigit(c) && c!='.') { return c; } i = 0; if (isdigit(c)) { while (isdigit(s[++i] = c = line[li++])) { ; } } if (c == '.') { while (isdigit(s[++i] = c = line[li++])) { ; } } s[i] = '\0'; --li; return NUMBER;}void push(double f){ int sp; double val[MAXVAL]; sp = 0; if (sp < MAXVAL) { val[sp++] = f; } else { printf("error: stack full, can't push %g\n", f); }}double pop(){ int sp; double val[MAXVAL]; sp = 0; if (sp > 0) { return val[--sp]; } else { printf("error: stack empty\n"); return 0.0; }}
书上的格式是第一种，但没有讲头文件和变量为什么要这样摆放
求教
[解决办法]
是你很多变量没有初始化，导致断言报错。
[解决办法]
两个程序一样吗？
assert wrong
[解决办法]
没看到什么区别
[解决办法]
可以，分析这样的程序只要看懂算法就好了，不要去纠结，编程的规范是在平时一步步养成的，多看点书，多查阅点资料，多上论坛问问题，从基础开始，
[解决办法]
头文件和变量在哪儿放不重要，只要放在使用之前就行