简单的C语言问题
先不说这个源码的别问题。。。为啥老是算的加法啊。。郁闷死了debug了judge明明不是1的啊。

C/C++ code

#include<stdio.h>char choice(void);char get(void);void now(int h);int main(void){    int ch,judge;    float first,second;   while((ch=choice())!='q'){        switch(ch)        {            case 'a':judge=1;break;            case 'b':judge=2;break;            case 'c':judge=3;break;            case 'd':judge=4;break;            default:printf("error");break;        }      now(judge);    }    printf("bye\n");  return 0;}char choice(void){   int ch;    printf("please enter the operation of your choice\n");    printf("a.add  b.subtract  c.multiply  d.divide  q.quit\n");    ch=get();    while((ch<'a'||ch>'d')&& ch!='q'){        printf("please respond with a,b,c,d or q\n");    ch=get();}    return ch;}char get(void){    int ch;    ch=getchar();    while(getchar()!='\n')        continue;    return ch;}void now(int h){ float a,b;   char ch;   printf("the first number:");   while((scanf("%f",&a)!=1))   {       while((ch=getchar())!='\n')           putchar(ch);      printf(":is not a unmber\n");    printf("please enter number\n");    printf("the first number:");   } printf("the second number:");   while((scanf("%f",&b)!=1))   {       while((ch=getchar())!='\n')           putchar(ch);    printf(":is not a unmber\n");    printf("please enter number\n");    printf("the second number:");   }   if(h=1)       printf("%f+%f=%f\n",a,b,a+b);   else if(h=2)       printf("%f-%f=%f\n",a,b,a-b);   else if(h=3)       printf("%f*%f=%f\n",a,b,a*b);   else if(h=4)       printf("%f/%f=%f\n",a,b,a/b);  }

先不说这个源码的别问题。。。为啥老是算的加法啊

[解决办法]
if(h=1)
都要该成
if(h==1)