服务器: 消息 170，级别 15，状态 1，行 14
SELECT c.ThreeCantonNumber as areano,c.ThreeCantonName,(a.FirstCantonName+b.SecondCantonName+c.ThreeCantonName) as AreaName from(
SELECT a.FirstCantonNumber,
b.SecondCantonNumber,
c.ThreeCantonNumber, a.FirstCantonName,
b.SecondCantonName,
c.ThreeCantonName
FROM dbo.T_FirstCanton a LEFT OUTER JOIN
dbo.T_SecondCanton b ON
a.FirstCantonNumber = b.FirstCantonNumber LEFT
OUTER JOIN
dbo.T_ThreeCanton c ON
b.SecondCantonNumber = c.SecondCantonNumber
)
服务器: 消息 170，级别 15，状态 1，行 14
第 14 行: ')' 附近有语法错误。


[解决办法]

SQL code

SELECT c.ThreeCantonNumber as areano,c.ThreeCantonName,(a.FirstCantonName+b.SecondCantonName+c.ThreeCantonName) as AreaName from(SELECT a.FirstCantonNumber,    b.SecondCantonNumber,    c.ThreeCantonNumber, a.FirstCantonName,    b.SecondCantonName,    c.ThreeCantonNameFROM dbo.T_FirstCanton a LEFT OUTER JOIN  dbo.T_SecondCanton b ON    a.FirstCantonNumber = b.FirstCantonNumber LEFT  OUTER JOIN  dbo.T_ThreeCanton c ON    b.SecondCantonNumber = c.SecondCantonNumber) t--加个别名
[解决办法]
SQL code
SELECT c.ThreeCantonNumber as areano,c.ThreeCantonName,(a.FirstCantonName+b.SecondCantonName+c.ThreeCantonName) as AreaName from(SELECT a.FirstCantonNumber,    b.SecondCantonNumber,    c.ThreeCantonNumber, a.FirstCantonName,    b.SecondCantonName,    c.ThreeCantonNameFROM dbo.T_FirstCanton a LEFT OUTER JOIN  dbo.T_SecondCanton b ON    a.FirstCantonNumber = b.FirstCantonNumber LEFT  OUTER JOIN  dbo.T_ThreeCanton c ON    b.SecondCantonNumber = c.SecondCantonNumber) as a --别名
[解决办法]
SQL code
SELECT ThreeCantonNumber as areano,ThreeCantonName,(FirstCantonName+SecondCantonName+ThreeCantonName) as AreaName from(SELECT a.FirstCantonNumber,    b.SecondCantonNumber,    c.ThreeCantonNumber, a.FirstCantonName,    b.SecondCantonName,    c.ThreeCantonNameFROM dbo.T_FirstCanton a LEFT OUTER JOIN  dbo.T_SecondCanton b ON    a.FirstCantonNumber = b.FirstCantonNumber LEFT  OUTER JOIN  dbo.T_ThreeCanton c ON    b.SecondCantonNumber = c.SecondCantonNumber) AS T
[解决办法]
SQL code
SELECT c.ThreeCantonNumber as areano,c.ThreeCantonName,(a.FirstCantonName+b.SecondCantonName+c.ThreeCantonName) as AreaName from(SELECT a.FirstCantonNumber,    b.SecondCantonNumber,    c.ThreeCantonNumber, a.FirstCantonName,    b.SecondCantonName,    c.ThreeCantonNameFROM dbo.T_FirstCanton a LEFT OUTER JOIN  dbo.T_SecondCanton b ON    a.FirstCantonNumber = b.FirstCantonNumber LEFT  OUTER JOIN  dbo.T_ThreeCanton c ON    b.SecondCantonNumber = c.SecondCantonNumber)tt
[解决办法]
直接

SQL code
SELECT c.ThreeCantonNumber as areano,c.ThreeCantonName,(a.FirstCantonName+b.SecondCantonName+c.ThreeCantonName) as AreaName FROM dbo.T_FirstCanton a LEFT OUTER JOIN  dbo.T_SecondCanton b ON    a.FirstCantonNumber = b.FirstCantonNumber LEFT  OUTER JOIN  dbo.T_ThreeCanton c ON    b.SecondCantonNumber = c.SecondCantonNumber
[解决办法]
子查询必须别名

SQL code
SELECT ThreeCantonNumber as areano,ThreeCantonName,(FirstCantonNameA+SecondCantonNameB+ThreeCantonNameC) as AreaName from(SELECT a.FirstCantonNumber,    b.SecondCantonNumber,    c.ThreeCantonNumber, a.FirstCantonName AS FirstCantonNameA ,   b.SecondCantonName AS FirstCantonNameB  ,    c.ThreeCantonName AS FirstCantonNameC  FROM dbo.T_FirstCanton a LEFT OUTER JOIN  dbo.T_SecondCanton b ON    a.FirstCantonNumber = b.FirstCantonNumber LEFT  OUTER JOIN  dbo.T_ThreeCanton c ON    b.SecondCantonNumber = c.SecondCantonNumber) AS T