请求把下面C#方法转成存储过程
作用是获取如下规则的编号 A+当天+序号。 A20110928001,A20110928002...

C# code

public string GetReceiveNumber()        {            string todayDateString = DateTime.Now.ToString("yyyyMMdd");            string sql = "select max(reveive_number) from material_receive where subString( reveive_number,2,8)='" + todayDateString + "' ";            DataSet ds = dal.GetDSBySQL(sql);            if (ds.Tables[0].Rows[0][0].ToString() == "")            {                return "A" + todayDateString + "001";            }            else            {                string sn = ds.Tables[0].Rows[0][0].ToString();                return sn.Substring(0, 9) + (int.Parse(sn.Substring(9)) + 1).ToString().PadLeft(3, '0');            }                            }

SQL code

---修正select   'A'+convert(varchar(12) , getdate(), 112 )+right('0000'+ltrim(row_number()over(order by getdate())),3)    /*-------------------A20110928001(1 行受影响)*/
[解决办法]
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SQL code
---修正

select 
  'A'+convert(varchar(12) , getdate(), 112 )+right('0000'+ltrim(row_number()over(order by getdate())),3)
  
  /*-------------------
A20110928001

(1 行受影响)*/