枚举类型问题
下面的程序有问题，为什么呢？
能不能详细的介绍下枚举的用法？


#include <stdio.h>
enum Ball{red=0,yellow=1,blue=2,white=3,black=4};

void Print(Ball ball)
{
switch(ball)
{
case red:
printf( " red ");
break;
case yellow:
printf( " yellow ");
break;
case blue:
printf( " blue ");
break;
case white:
printf( " white ");
break;
case black:
printf( " balck ");
}
}

int main(void)
{

enum Ball first,second,third;
int num=0;

for(first=red;first <=black;first+=1)
{
for(second=red;second <=black;second++)
{
for(third=red;third <=black;third++)
{
if((first!=second)&&(second!=third)&&(first!=third))
{
Print(first);
Print(second);
Print(third);
num++;
printf( "\n ");
}

}
}
}
printf( "total number is :%d\n ",num);

return 0;
}



[解决办法]
//enum Ball first,second,third;
int first, second, third;

[解决办法]
说实话，枚举我也没彻底弄明白
不过就我理解，是一系列的常数变量，懒得一个个申明，所以一次枚举出来
即： 枚举 == 一堆一堆的常数变量
你的错误在于
enum Ball first,second,third;
~~~~~~~~~~ 应该是 int first, second, third