python的hash计算，不懂
- Python code
def tesHash(fileName): """Returns tes4's two hash values for filename. Based on TimeSlips code with cleanup and pythonization.""" root,ext = os.path.splitext(fileName.lower()) #--"bob.dds" >> root = "bob", ext = ".dds" #--Hash1 chars = map(ord,root) #--'bob' >> chars = [98,11,98] hash1 = chars[-1] | (0,chars[-2])[len(chars)>2]<<8 | len(chars)<<16 | chars[0]<<24 #--(a,b)[test] is similar to test?a:b in C. (Except that evaluation is not shortcut.) if ext == '.kf': hash1 |= 0x80 elif ext == '.nif': hash1 |= 0x8000 elif ext == '.dds': hash1 |= 0x8080 elif ext == '.wav': hash1 |= 0x80000000 #--Hash2 #--Python integers have no upper limit. Use uintMask to restrict these to 32 bits. uintMask, hash2, hash3 = 0xFFFFFFFF, 0, 0 for char in chars[1:-2]: #--Slice of the chars array hash2 = ((hash2 * 0x1003f) + char ) & uintMask for char in map(ord,ext): hash3 = ((hash3 * 0x1003F) + char ) & uintMask hash2 = (hash2 + hash3) & uintMask #--Done return (hash2<<32) + hash1 #--Return as uint64
这是一段计算值文件名hash的代码，小弟初学python实在是看不懂，哪位大哥能帮我看看是什么意思么，如果可以的话，写个伪代码或者C代码都行，上面的根据map函数啊，(0,chars[-2])[len(chars)>2]<<8是什么意思都不清楚。
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你的问题在注释里都有回答了：
1. map: chars = map(ord,root) #--'bob' >> chars = [98,11,98]
map(function, list) = [function(list[0]), function(list[1]), ...]
2. 第二个问题相关的代码行下有注释：
#--(a,b)[test] is similar to test?a:b in C. (Except that evaluation is not shortcut.)
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