c++基础题
输入两个字符串s和t，打印出t在s中的出现的位置，并输出出现的次数如输入：s=qwqwertqweqqqq，t=qw
这个怎么写？

[解决办法]

C/C++ code

#include<stdio.h>#include<string.h>int main(){    char s[128],t[128];    char *pTemp;    int nLenS,nLenT,nCount=0;    memset(s, 0, sizeof(s));    memset(t, 0, sizeof(t));    printf("please input s :\n");    scanf("%s", s);    printf("please input t :\n");    scanf("%s", t);    nLenS = strlen(s);    nLenT = strlen(t);    pTemp = s;    while(1)    {        if(strstr(pTemp,t) != NULL)        {            nCount++;            pTemp = strstr(pTemp,t) + nLenT;        }        else        {            break;        }    }    printf("the times : %d", nCount);    return 0;}
[解决办法]
这个可以直接运行：
C/C++ code
#include <iostream>using std::cout;using std::endl;                 int main(){    const char *s = "qwqwertqweqqqq";    const char *target = "qw";    int j,k,count = 0,position[20];    for(int i = 0;s[i] != '\0'; ++i)    {        for(j=0,k = i;target[j] != '\0';++j,++k)        {            if(s[k] != target[j])            break;        }        if(target[j] == '\0')        {            position[count] = i + 1;            ++count;        }    }    cout << "总共出现的次数:" << count << endl;    cout << "出现的位置:" ;    for(int i = 0; i < count; ++i)    {        cout << position[i] << "  ";    }    cout << endl;         return 0;}
[解决办法]
bool outPut(char *str1,char *str2)
{
 assert(str1 && str2);
 assert(strlen(str1)>strlen(str2));
 char* ch1=str1;
 char* ch2=str2;
 int i=0;
 int count=0;
 while(*ch1)
 {
     if(!*ch2)
     {
         cout<<i-strlen(str2)<<"  ";
         ch2=str2;
         count++;
     }
     if(*ch1==*ch2)
     {
         ch1++;
         ch2++;
     }
     else
     ch1++;
     i++;
 }
 cout<<endl;
 cout<<" 次数："<<count;
}