c++关于容器的insert用法
#include <iostream>
#include <list>
#include <deque>
using namespace std;

int main()
{
int number;
list<int> llist;

cout << "Enter some numbers (CTRL + Z to end)" << endl;
while(cin >> number)
llist.push_back(number);

list<int>::iterator bgter = llist.begin();
list<int>::iterator edter = llist.end();
if(llist.size() % 2 == 1) { //list容器的元素为奇数
deque<int> que_1;个数
deque<int>::iterator dqter = que_1.begin();
que_1.insert(dqter, bgter, edter); //编译器显示这里有问题
for(deque<int>::iterator beg_1 = que_1.begin(); beg_1 != que_1.end(); beg_1++)
cout << *beg_1 << " ";
cout << endl;
}
if(llist.size() % 2 == 0) { //list容器的元素个数为奇数
deque<int> que_2;
que_2.insert(que_2.end(), bgter, edter); //编译器显示这里有问题
for(deque<int>::iterator beg_2 = que_2.begin(); beg_2 != que_2.end(); beg_2++)
cout << *beg_2 << " ";
cout << endl;
}

return 0;
}


请问为什么提示'void __thiscall std::deque<int,class std::allocator<int> >::insert(class std::deque<int,class std::allocator<int> >::iterator,unsigned int,const int &)' : cannot convert parameter 2 from 'class std::li
st<int,class std::allocator<int> >::iterator' to 'unsigned int'

[解决办法]
deque<int> que_1;个数
这一句的个数要加注释，修改为：
deque<int> que_1;//个数

除了这个没其它问题啊，我的编译器可以正确运行，不知楼主用的什么编译器

[解决办法]
加个注释就行了···
[解决办法]
怎么做？

C/C++ code

#include <iostream>#include <list>#include <deque>using namespace std;int main(){    int number;    list<int> llist;    cout << "Enter some numbers (CTRL + Z to end)" << endl;    while(cin >> number)        llist.push_back(number);    list<int>::iterator bgter = llist.begin();    list<int>::iterator edter = llist.end();    if(llist.size() % 2 == 1) { //list容器的元素为奇数          deque<int> que_1;//个数            deque<int>::iterator dqter = que_1.begin();        que_1.insert(dqter, bgter, edter); //编译器显示这里有问题        for(deque<int>::iterator beg_1 = que_1.begin(); beg_1 != que_1.end(); beg_1++)            cout << *beg_1 << " ";        cout << endl;    }    if(llist.size() % 2 == 0) { //list容器的元素个数为奇数          deque<int> que_2;        que_2.insert(que_2.end(), bgter, edter); //编译器显示这里有问题        for(deque<int>::iterator beg_2 = que_2.begin(); beg_2 != que_2.end(); beg_2++)            cout << *beg_2 << " ";        cout << endl;    }    return 0;}