QT线程独占
各位大虾,我做了个线程独占的测试程序,代码如下:
/******************定义两个线程thread1和thread2**************************/
#ifndef TEST_H
#define TEST_H
#include <qthread.h>
#include <iostream.h>
#include <qmutex.h>
#include <qwaitcondition.h>
class Thread1:public QThread{
public:
Thread1(QMutex *mutex_1, QWaitCondition *cond_1){};
~Thread1(){};
virtual run(){
for(int i=0;i <5;i++){
cout < < "thread1 ping " < <endl;
sleep(1);
}
};
};
class Thread2:public QThread{
public:
Thread2(QMutex *mutex_2, QWaitCondition *cond_2){};
~Thread2(){};
virtual run(){
for(int i=0;i <5;i++){
cout < < "------thread2 ping---- " < <endl;
sleep(2);
}
};
};
#endif
/*****************主程序如下********************/
#include "test.h "
int main(int argc, char *argv[])
{
QMutex mutex;
QWaitCondition condition;
Thread1 *thread1;
Thtead2 *thread2;
mutex.lock();
thread1=new Thread1(&mutex, &condition);
thread1-> start();
mutex.unlock();
mutex.lock();
thread2=new Thread2(&mutex,&condition);
thread2-> start();
mutex.unlock();
return 0;
}
可是出现的是如下的结果;
thread1 ping
thread1 ping
------thread2 ping----
thread1 ping
thread1 ping
------thread2 ping----
thread1 ping
------thread2 ping----

------thread2 ping----
------thread2 ping----
不是我想要的结果,我想要的是:
thread1 ping
thread1 ping
thread1 ping
thread1 ping
thread1 ping
------thread2 ping----
------thread2 ping----
------thread2 ping----
------thread2 ping----
感觉好象是mutex.lock()根本就不起作用,没有锁住线程,我知道如果我用thread1-> wait()和thread2-> wait()可以得到我想要的结果,但是我想知道,mutex.lock()这个函数怎么用,因为我的程序里需要用到互斥线程去访问公共变量.那么,各位大虾,我怎么样使用mutex.lock()得到我想要的结果呢?



[解决办法]
对于这种多任务的操作系统，
我也想知道怎么让一个线程独占资源的？

[解决办法]
virtual run(){
//这里lock
for(int i=0;i <5;i++){
cout < < "thread1 ping " < <endl;
sleep(1);
}
//这里unlock
};

线程2和线程1加锁解锁的地方一样!!!