一元二次方程！！！！c++的收藏起来哈！！
//*********************************************
//RootConstructor.cpp
#include <iostream>
#include <cmath>
using namespace std;

class RootConstructor
{
private:
int a,b,c;
double x1,x2;
public:
RootConstructor(int i,int j,int k)
{
a=i; b=j; c=k;
x1=(-b+sqrt(b*b-4*a*c))/(2*a);
x2=(-b-sqrt(b*b-4*a*c))/(2*a);
}
void disp()
{
cout<<"您输入的方程是：\n";
cout<<a<<"x^2";

if (b>0)
cout <<"+" <<b <<"x";
else
cout<<b <<"x";

if (c>0)
cout<<"+"<<c<<"=0";
else
cout<<c<<"=0";

cout<<"\n下面是方程的根：\n";
cout <<"x1=" <<x1 <<endl;
cout <<"x2=" <<x2 <<endl;
}
};

int main()
{
RootConstructor objS(1,-5,6);
objS.disp();
return 0;
}

//*********************************************

[解决办法]

C/C++ code

//*********************************************//RootConstructor.cpp#include <iostream>#include <cmath>using namespace std;class RootConstructor {private:    double a,b,c;    double x1,x2;public:    RootConstructor(double i,double j,double k) {        a=i; b=j; c=k;        if (b*b-4*a*c<0.000001) {            x1=0.0;            x2=0.0;        } else {            x1=(-b+sqrt(b*b-4.0*a*c))/(2.0*a);            x2=(-b-sqrt(b*b-4.0*a*c))/(2.0*a);        }    }    void roots() {        cout<<"您输入的方程是：\n";        cout<<a<<"x^2";        if (b<-0.000001)            cout<< b <<"x";        else if (0.000001<b)            cout<< "+"<< b <<"x";        if (c<-0.000001)            cout<< c <<"=0";        else if (0.000001<c)            cout<< "+"<< c <<"=0";        if (x1==0.0 && x2==0.0) {            cout<<"\n此方程无解。\n";        } else {            cout<<"\n下面是方程的根：\n";            cout <<"x1=" <<x1 <<endl;            cout <<"x2=" <<x2 <<endl;        }    }};int main() {    RootConstructor equation(1.0,-5.0,6.0);    equation.roots();    return 0;}//*********************************************
[解决办法]
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引用:

C/C++ code
//*********************************************
//RootConstructor.cpp
#include <iostream>
#include <cmath>
using namespace std;

class RootConstructor {
p……